20 points for correct answer and a brainliest for first correct answer!

How can a frequency table or histogram help you organize and analyze data?

Len [333]

Answer:

$\red{{\sf{NONSENSE=}}}$

$\blue{{\sf{REPORT}}}$

$\color {red}{•}\color {orange}{•}\color {yellow}{•}\color {lime}{•}\color {green}{•}\color {cyan}{•}\color {aquamarine}{•}\color {indigo}{•}\color {blue}{•}\color {violet}{•}\color {blueviolet}{•}\color {pink}{•}\color {magenta}{•} \color {brown}{•}\color {gray}{•}\color {black}{•}$

4 0

2 years ago

Read 2 more answers

Ella grew 3 over 4 of an inch last year. Ben grew 2 over 3 of an inch last year. How much more did Ella grow than Ben last year?

IrinaK [193]

Answer:

Ella grew $\frac{1}{12}$ of an inch more

Step-by-step explanation:

For this problem, you want to subtract Ben's growth from Ella's.

This expression would be $\frac{3}{4}$ - $\frac{2}{3}$ .

To work these out, they must have the same denominator (which should be the lowest common multiple or LCM).

In this case, the LCM is 12, so you want to multiply each side so the denominator is 12. This means the first fraction should be multiplied by $\frac{3}{3}$ and the second by $\frac{4}{4}$ .

This makes the expression $\frac{9}{12}$ - $\frac{8}{12}$ , which equals $\frac{1}{12}$ .

**This content involves adding and subtracting fractions, which you may want to revise. I'm always happy to help!

7 0

2 years ago

Solve by completing the square and show steps <br> x^(2)+6x+5=0

Crazy boy [7]

X ^2 +6x+ 5
(x+2)(x+3)

2 + 3 = 5
While also 2•3= 6
The two numbers have to equal b when multiplied and c when added

4 0

2 years ago

Of 560 marbles in a bag, 65% are red and the rest are blue. After 28 red marbles are replaced with blue ones, how many blue marb

jonny [76]

Answer: The answer is 400 blue marbles.

Step-by-step explanation: Given that there are 560 marbles in a bag, out of which 65% are red and rest are blue.

So, number of red marbles is

$n_r=65\%\times 560=\dfrac{65}{100}\times 560=364,$

and number of blue marbles is

$n_b=560-364=196.$

Now, if 28 red marbles are replaced by blue marbles, the the new number of red and blue marbles will be

$n_r^\prime=364-28=336~~~\textup{and}~~~n_b^\prime=196+28=224.$

Now, to get 65% of the marbles blue, we need to add some more blue marbles to the bag. Let 'x' number of blue marbles are added to the bag, then

$65\%\times (560+x)=224+x\\\\\Rightarrow \dfrac{65}{100}\times (560+x)=224+x\\\\\Rightarrow 13(560+x)=20(224+x)\\\\\Rightarrow 7280+13x=4480+20x\\\\\Rightarrow 7x=2800\\\\\Rightarrow x=400.$