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zhannawk [14.2K]
3 years ago
9

What is known as the amount of mass in

Physics
2 answers:
Stells [14]3 years ago
8 0
Density is the known amount of mass in a given volume. (A.- density)
k0ka [10]3 years ago
7 0
I believe the answer is D. Have a good day.
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An airplane flies horizontally with a constant speed of 155.0 m/s at an unknown altitude. A package is released out of the airpl
vladimir1956 [14]

Answer:

 y₀ = 1020.3 m

Explanation:

This is a projectile launching exercise, in this case as the package is released its initial vertical velocity is zero.

            y = y₀ + v_{oy} t - ½ g t²

when it reaches the ground its height is zero

           0 = y₀ + 0 - ½ g t²

           y₀ = ½ g t²

           

let's calculate

         y₀ = ½ 9.8 14.43²

         y₀ = 1020.3 m

8 0
3 years ago
In three to five sentences, identify the acid, base, conjugate acid, and conjugate base. Use patterns in the periodic table to e
Oliga [24]

A conjugate acid is formed from the base  by accepting a proton from the acid .

A conjugate base is obtained from the Brownstead - Lowry acid when it looses a proton while the conjugate acid is obtained from the Brownstead - Lowry base when it accepts a proton. In the Brownstead - Lowry sense, acid base reaction involves the loss or gain of a proton.

Consider the hypothetical reaction; AH + :B ⇄ BH + :A. The specie BH is the conjugate acid while the specie  :B is the  Brownstead - Lowry base . The specie :A is the conjugate base while the specie AH is the  Brownstead - Lowry acid.

Learn more about conjugate acid: brainly.com/question/10468518

6 0
3 years ago
_ Ba+_O2 =_BaO how do I balance this?
astraxan [27]

Answer:

02-ba=_4

Explanation:

5 0
3 years ago
Answer fast please !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
iogann1982 [59]
I believe it's the the third one. :)
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8 0
3 years ago
Read 2 more answers
Quinn accelerates her skateboard along a straight path from 0 m/s to 4.0 m/s
umka2103 [35]
  • initial velocity=u=0m/s
  • Final velocity=v=4m/s
  • Time=t=2.5s

\\ \sf\longmapsto Acceleration=\dfrac{v-u}{t}

\\ \sf\longmapsto Acceleration=\dfrac{4-0}{2.5}

\\ \sf\longmapsto Acceleration=\dfrac{4}{2.5}

\\ \sf\longmapsto Acceleration=1.6m/s^2

8 0
3 years ago
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