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Nesterboy [21]
3 years ago
6

Two objects each with a mass of 5x10^15 kg have a gravitational

Physics
1 answer:
kipiarov [429]3 years ago
6 0

Answer:

Distance, r = 700.31 m

Explanation:

Mass of two objects, m_1=m_2=5\times 10^{15}\ kg

Force between the objects , F=3.4\times 10^{15}\ N

We need to find the distance between the two objects. The force of gravitational between two objects is given by :

F=G\dfrac{m_1m_2}{r^2}\\\\r=\sqrt{\dfrac{Gm_1m_2}{F}} \\\\r=\sqrt{\dfrac{6.67\times 10^{-11}\times (5\times 10^{15})^2}{3.4\times 10^{15}}}\\\\=700.31\ m

So, the distance between the objects is 700.31 m.

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- A straight wire, 0.20 m long, moves at a constant speed of 7.0 m/s
Elis [28]

(a) The emf induced in the wire is 0.112 V.

(b) The direction of the current will into the page.

(c) The polarity of A will be positive and L will be negative.

(d)  The current flowing through the wire is 0.224 A.

<h3>EMF induced in the wire</h3>

The emf induced in the wire is calculated as follows;

EMF = BLv

EMF = (8 x 10⁻²) x 0.2 x 7

EMF = 0.112 V

<h3>Direction of the current</h3>

Since, the magnetic field is out of the page, the current will follow counter clockwise and will point into the page.

<h3>Polarity of point A and point L</h3>

The current is flowing counter currently, hence the polarity of A will be positive and L will be negative.

<h3>Current through the wire</h3>

V = IR

I = V/R

I = (0.112)/0.5

I = 0.224 A

Learn more about current here: brainly.com/question/24858512

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7 0
2 years ago
Help please help me?
Andrews [41]

Answer:

C. Planet D has the greatest mass and will exert a greater gravitational force

6 0
3 years ago
A light wave encounters a partial physical barrier, such as a wall with a hole in it. What is MOST LIKELY to occur?
tatiyna
Most likely, the light wave will be absorbed by the wall. Without any information as to the size and color of the wall, the location and size of the hole, or the location of the light wave, this is a generalized probability problem. For all of the places the light could be, it's more likely that it hits the wall than the hole (if the hole is less than 50% of the area of the wall).
5 0
3 years ago
Read 2 more answers
A point charge q1q1 is held stationary at the origin. A second charge q2q2 is placed at point aa, and the electric potential ene
Yuri [45]

Explanation:

The given data is as follows.

            U_{a} = 5.4 \times 10^{-8} J

        W_{/text{a to b}} = -1.9 \times 10^{-8} J

        Electric potential energy (U_{b}) = ?

Formula to calculate electric potential energy is as follows.

            U_{b} = U_{a} - W_{/text{a to b}}

                        = 5.4 \times 10^{-8} J - (-1.9 \times 10^{-8} J)

                        = 7.3 \times 10^{-8} J

Thus, we can conclude that the electric potential energy of the pair of charges when the second charge is at point b is 7.3 \times 10^{-8} J.

6 0
4 years ago
Consider a transformer. used to recharge rechargeable flashlight batteries, that has 500 turns in its primary coil, 3 turns in i
Rashid [163]

Answer:

<em>a) 0.72 V</em>

<em>b) 19.2 mA</em>

<em>c) 2.304 Watts</em>

Explanation:

A transformer is used to step-up or step-down voltage and current. It uses the principle of electromagnetic induction. When the primary coil is greater than the secondary coil, the it is a step-down transformer, and when the primary coil is less than the secondary coil, the it is a step-up transformer.

number of primary turns = N_{p} = 500 turns

input voltage = V_{p} = 120 V

number of secondary turns = N_{s} = 3 turns

output voltage = V_{s} = ?

using the equation for a transformer

\frac{V_{s} }{V_{p} }  = \frac{N_{s} }{N_{p} }

substituting values, we have

\frac{V_{s} }{120 }  = \frac{3 }{500} }

500V_{p}  = 120*3\\500V_{p} = 360

V_{p} = 360/500 =<em> 0.72 V</em>

<em></em>

b) by law of energy conservation,

I_{P}V_{p} = I_{s}V_{s}

where

I_{p} = input current = ?

I_{s} = output voltage = 3.2 A

V_{s} = output voltage = 0.72 V

V_{p} = input voltage = 120 V

substituting values, we have

120I_{p} = 3.2 x 0.72

120I_{p} = 2.304

I_{p}  = 2.304/120 = 0.0192 A

= <em>19.2 mA</em>

<em></em>

c) power input = I_{p} V_{p}

==> 0.0192 x 120 = <em>2.304 Watts</em>

7 0
3 years ago
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