Which is a diatomic molecule?A.He B.O2 C.NaCl D.CuF2

Can someone help me ASAP

Phantasy [73]

Well I don't know. Let's actually LOOK at the picture and see if that helps.

A, B, C, and D all have the same TOTAL length, but A has the most waves crammed into that same total length.

By golly, that means the length of each wave in A must be shorter than each wave in B, C, or D.

The correct choice is A . Looking at the picture did the trick !

7 0

3 years ago

In both the camera and the __________, light enters a narrow opening and is projected onto a photosensitive surface. Group of an

Citrus2011 [14]

Answer: The HUMAN EYE

Explanation:

The human eye is made up of different parts which ranges from controlling the amount of light that enters the eye to the focusing of the image that is formed. The camera is a device which is both mechanically and electronically operated which shares a number of similarities with the eye.

In the human eye, the IRIS helps to regulate the amount of rays passing through the pupil to the lens by either contracting or dilating in light or dark environment respectively. While in the camera, the DIAPHRAGM controls the amount of light entering the camera.

The PUPIL serves as the passage for light into the eye while in the camera, the APERTURE does the same.

The photosensitive surface in the eye is the YELLOW SPOT while in the camera, the photosensitive surface is the PHOTOGRAPHIC FILM.

5 0

2 years ago

An isolated conducting sphere has a 17 cm radius. One wire carries a current of 1.0000020 A into it. Another wire carries a curr

notsponge [240]

14 ms is required to reach the potential of 1500 V.

Explanation:

The current is measured as the amount of charge traveling per unit time. So the charge of electrons required for each current is determined as the product of current with time.

$Charge = Current \times Time$

As two different current is passing at two different times, the net charge will be the different in current. So,

$\text { Charge }=(1.0000020-1.0000000) \times t=2 \times 10^{-6} \times t$

The electric voltage on the surface of cylinder can be obtained as the ratio of charge to the radius of the cylinder.

$V=\frac{k q}{R}$

Here $k = 9 * 10^9$ , q is the charge and R is the radius. As $q=2 \times 10^{-6} \times t$ and R =17 cm = 0.17 m, then the voltage will be

$V=\frac{9 \times 10^{9} \times 2 \times 10^{-6} \times t}{0.17}$

The time is required to find to reach the voltage of 1500 V, so

$1500 =\frac{9 \times 10^{9} \times 2 \times 10^{-6} \times t}{0.17}$

$\begin{aligned}&t=\frac{1500 \times 0.17}{\left(9 \times 10^{9} \times 2 \times 10^{-6}\right)}\\&t=14.1666 \times 10^{-3} s=14\ \mathrm{ms}\end{aligned}$

So, 14 ms is required to reach the potential of 1500 V.

3 0

3 years ago

Within the theory of G relativity what, exactly, is meant by " the speed of light WITHIN A VACUUM" ? & what does that have t

Ber [7]

The speed of light "within a vacuum" refers to the speed of electromagnetic radiation propagating in empty space, in the complete absence of matter. This is an important distinction because light travels slower in material media and the theory of relativity is concerned with the speed only in vacuum. In fact, the theory of relativity and the "speed of light" actually have nothing to do with light at all. The theory deals primarily with the relation between space and time and weaves them into an overarching structure called spacetime. So where does the "speed of light" fit into this? It turns out that in order to talk about space and time as different components of the same thing (spacetime) they must have the same units. That is, to get space (meters) and time (seconds) into similar units, there has to be a conversion factor. This turns out to be a velocity. Note that multiplying time by a velocity gives a unit conversion of
$seconds \times \frac{meters}{seconds} =meters$
This is why we can talk about lightyears. It's not a unit of time, but distance light travels in a year. We are now free to define distance as a unit of time because we have a way to convert them.
As it turns out light is not special in that it gets to travel faster than anything else. Firstly, other things travel that fast too (gravity and information to name two). But NO events or information can travel faster than this. Not because they are not allowed to beat light to the finish line---remember my claim that light has nothing to do with it. It's because this speed (called "c") converts space and time. A speed greater than c isn't unobtainable---it simply does not exist. Period. Just like I can't travel 10 meters without actually moving 10 meters, I cannot travel 10 meters without also "traveling" at least about 33 nanoseconds (about the time it takes light to get 10 meters) There is simply no way to get there in less time, anymore than there is a way to walk 10 meters by only walking 5.
We don't see this in our daily life because it is not obvious that space and time are intertwined this way. This is a result of our lives spent at such slow speeds relative to the things around us.
This is the fundamental part to the Special Theory of Relativity (what you called the "FIRST" part of the theory) Here is where Einstein laid out the idea of spacetime and the idea that events (information) itself propagates at a fixed speed that, unlike light, does not slow down in any medium. The idea that what is happening "now" for you is not the same thing as what is "now" for distant observers or observers that are moving relative to you. It's also where he proposed of a conversion factor between space and time, which turned out to be the speed of light in vacuum.

3 0

3 years ago

The masses are m1 = m, with initial velocity 2v0, and m2 = 7.4m, with initial velocity v0. Due to the collision, they stick toge

lesya [120]

Answer:

Loss, $\Delta E=-10.63\ J$