Answer:
3 volts
Explanation:
Number of turns in primary coil = = 100
Number of turns in secondary coil = = 200
Voltage across primary coil = = 1.5 volts
Voltage across secondary coil = = ?
In a transformer, the ratio of number of turns of primary to secondary coil is equal to the ratio of the respective voltages i.e.
Using the given values, we get:
Thus, the voltage measure across secondary coil would be 3 volts
Explanation:
Given that,
The voltages across them are 40,50 and 60 volts respectively, and the charge on each condenser is 6×10⁻⁸ C.
(a) Capacitance of capacitor 1,
Capacitance of capacitor 2,
Capacitance of capacitor 3,
(b) The equivalent capacitance in series combination is :
Hence, this is the required solution.
The magnitude of the magnetic force on the proton is 1.25× 10—¹³ N.
Speed of the proton = 5.02 × 10 ⁶ m /a
Angel of between the velocity and the magnetic force = 60 °
The magnitude of magnetic field B = 0.180 T
The magnitude of the magnetic force on the proton is,
Therefore, the magnitude of the magnetic force on the proton is 1.25× 10—¹³ N.
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