1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Elis [28]
2 years ago
10

How many meters are in a kilometer.

Chemistry
1 answer:
Anika [276]2 years ago
4 0

Answer:

1,000 meters in 1 kilometer

Explanation:

You might be interested in
If 100 yards = 1 football field, what is the length, in meters, of 4.9<br> football fields?
Veseljchak [2.6K]
* Answer: 448.056 meters *
——
1 yard = .9144 meters (according to Google)
100 yards= 91.44 meters
——
100*4.9= 490 yards
490 yards = 448.056 meters

* 4.9 Football fields= 448.056 meters *

I hope this helps! :)
4 0
2 years ago
Kc = 3.07 x 10-4 at 24°C for 2NOBr(g) ↔ 2NO(g) + Br2(g). If the initial concentration of NOBr = 0.878 M, what is the equilibrium
pav-90 [236]

Answer:

The equilibrium concentration of NO is 0.02124 M.

Explanation:

Given that,

Initial concentration of NOBr = 0.878 M

k_{c}=3.07\times10^{-4}

Temperature = 24°C

We know that,

The balance equation is

2NOBr\Rightarrow 2NO+Br_{2}

Initial concentration is,

0.878\Rightarrow 0+0

Concentration is,

-2x\Rightarrow 2x+x

Equilibrium concentration

0.878-2x\Rightarrow 2x+x

We need to calculate the value of x

Using formula of concentration

k_{c}=\dfrac{[NO][Br_{2}]}{[NOBr]^2}

Put the value into the formula

3.07\times10^{-4}=\dfrac{[2x][x]}{[0.878-2x]^2}

2x^2=3.07\times10^{-4}\times(0.878)^2+3.07\times10^{-4}\times4x^2-2\times2x\times0.878\times3\times10^{-4}

2x^2=0.0002367+0.001228x^2-0.0010536x

2x^2-0.001228x^2+0.0010536x-0.0002367=0

1.998772x^2+0.0010536x-0.0002367=0

x=0, 0.01062

We need to calculate the equilibrium concentration of NO

Using formula of concentration of NO

concentration\ of\ NO=2x

Put the value of x

concentration\ of\ NO=2\times0.01062

concentration\ of\ NO=0.02124

Hence, The equilibrium concentration of NO is 0.02124 M.

7 0
3 years ago
Which of the following would lose heat the fastest?
Molodets [167]

Answer:

15 grams of water

Explanation:

15 grams of water of water would lose heat the faster compared to higher masses of water.

Water generally is a poor conductor heat.

  • To heat up a unit of water, significant amount of energy must be added to the body of water.
  • With time, the body continues to increase in temperature.
  • A 500g mass of water will take more time to lose heat.
5 0
3 years ago
How much milk at 1 degrees Celsius is needed to reduce the temperature of
Kobotan [32]
It’s can go down to 50 degrees soo that can do
8 0
2 years ago
What do elements in the first two columns of the periodic table have in common?
coldgirl [10]

Answer: b.) they tend to lose electrons to gain stability

Explanation:

5 0
3 years ago
Other questions:
  • An atom's configuration based on its number of electrons ends at 3p3. Another atom has nine more electrons. Starting at 3p, what
    15·2 answers
  • What are the answers of the parts? All of them please.
    9·1 answer
  • Ice will ________ in water.<br> A. float<br> B. sink<br> C. stay the same
    7·2 answers
  • 2. You used a calorimeter in the Heat Transfer lab. Explain how the calorimeter works, and how to calculate the heat given off o
    10·1 answer
  • Which title is most appropriate for this table? ANSWERS: Uses of Functional Groups Involving Oxygen Natural Sources of Functiona
    7·1 answer
  • Surface water is found in oceans, lakes, reservoirs, streams, rivers,and glaciers. Lakes, rivers, and reservoirs are where human
    8·1 answer
  • When an isotope emits an alpha particle, its atomic number
    13·1 answer
  • C3H8+5O2 →3CO2+4H20,
    12·1 answer
  • Which type of energy is thermal energy a form of? Hurry it's timed!
    15·2 answers
  • Sulfur is yellow, solid, nonmetal. what other elements is likely also a nonmetal?
    14·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!