If I'm understanding the question they should be those. If you want to go left then the would be
Left
0.00347
0.008132
Right
347.
8,132.
The answer is C because multiplication comes first
Answer:
Distance= 6.6 miles
Bearing= N 62.854°W
Step-by-step explanation:
Let's determine angle b first
Angle b=20° (alternate angles)
Using cosine rule
Let the distance between the liner and the port be x
X² =8.8²+2.4²-2(8.8)(2.4)cos20
X²= 77.44 + 5.76-(39.69)
X²= 43.51
X= √43.51
X= 6.596
X= 6.6 miles
Let's determine the angles within the triangle using sine rule
2.4/sin b = 6.6/sin20
(2.4*sin20)/6.6= sin b
0.1244 = sin b
7.146= b°
Angle c= 180-20-7.146
Angle c= 152.854°
For the bearing
110+7.146= 117.146
180-117.146= 62.854°
Bearing= N 62.854°W
No offense but the question dosen't make sense
The answer is
date
1 2 3 4 5 31
r1 r2 r3 r4 r5 . . . r31
1gm 2gms 3<span>gms 4gms 5gms . . . 31gms
r1+r2+ .... +r31= 31(31+1) /2=496gms (31 rings)
he only made 5 rings
31 rings----------> 496 gms
5 rings ------------> ? = 5 x496 / 31=80 gms
</span><span> the weights of those 5 rings was 80 gms</span>