Answer:
50$
Step-by-step explanation:
First money he had = 20$
Second = 10$ * 3 = 30$
Total money he had = 20$+30$ =
= 50$
Mark as Brainliest
Answer:
Step-by-step explanation:
Given are the vertices of a quadrilateral.
WE have to find the name of the quadrilateral
WE have slope of AC = (5-1)/(7-3) = 1
and slope of BD = (2-5)/(7-4) = -1
Since m1m2 =-1 we get
the diagonals cut at right angles
This property is special property for square, rhombus and kite only.
Let us check if diagonals bisect each other
Mid point of AC = 
Mid point of BD =
Since diagonals do not bisect this is neither rhombus nor square.
Only possibility is kite
Answer:
47
Step-by-step explanation:
1. #2 and #3 reveal that it must be between 31 to 89
2. #4 and #5 reveals that the answer is one of these numbers:
44, 45, 46, 47, 48, 49
64, 65, 66, 67, 68, 69
84, 85, 86, 87, 88, 89
This is because only 4, 6, and 8 are divisible by 2
3. You must add up all the numbers to see which ones add up to either 11 or 12.
4 + 7 = 11
4 + 8 = 12
6 + 5 = 11
6 + 6 = 12
8 + 4 = 12
This means that these are the following numbers: 47, 48, 65, 66, 84
4. #7 says that you must find the smallest number. The smallest number left is 47.
Answer:
the answer is 2. there arwnt any number lines so
Answer:
1) A. 5 + 2.75 * S ≤ 21
2) 5
Step-by-step explanation:
Well there is an initial price of $5 and $2.75 per stop, and she can only spend less than or equal to $21 we can make the following inequality,
5 + 2.75 * S ≤ 21,
<em>Meaning, Q.1 is A</em>
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Now #2 is 5 stops because if we plug in 5 for s we get 18.75.
<em>Thus, the most amount of stops she can afford is 5.</em>
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<em>Hope this helps :)</em>
