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Neko [114]
3 years ago
8

Rocks are classified as sedimentary, metamorphic, or igneous on the basis of

Chemistry
2 answers:
oee [108]3 years ago
7 0
The answer is b. way the rocks were formed.
olganol [36]3 years ago
7 0
The answer is B hope it correct cause I need more information
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Calculate the volume of 0.100 m hcl required to neutralize 1.00 g of ba(oh)2 (molar mass = 171.3 g/mol).
dedylja [7]

The balanced chemical equation between HCl and Ba(OH)_{2} is:

2HCl (aq) + Ba(OH)_{2}(aq) -->BaCl_{2}(aq) + 2 H_{2}O(l)

Moles of Ba(OH)_{2} = 1.00 g Ba(OH)_{2} * \frac{1 mol Ba(OH)_{2}}{171.3 g Ba(OH)_{2}} = 0.00584 mol Ba(OH)_{2}

Moles of HCl required to neutralize Ba(OH)_{2}:

0.00584 mol Ba(OH)_{2} * \frac{ 2 mol HCl}{1 mol Ba(OH)_{2}} =   0.01168 mol HCl

Calculating the volume of HCl from moles and molarity:

0.01168 mol HCl * \frac{1 L}{0.100 mol} * \frac{1000 mL}{1 L} = 116.8 mL

7 0
3 years ago
Read 2 more answers
When 12 moles of o2 react with 1.1 mole of c10h8 what is the limiting reactant?
Trava [24]
1.1   moles   of C10H8  is the  limiting  reagent  in   the  reaction between   reaction  C10H8   and   O2
.
C10H8  +  12O2  ---->  10CO2   + 4H2O

C10H8  is  the  limiting   reagent   since   1.1  moles  of  C10H8  is  totally   consumed   during  the  reaction
6 0
3 years ago
Read 2 more answers
10. What are the reactants and the products in the
Ivahew [28]

Answer:

B

Explanation:

Reactants: H20 and Oz; Product: H202

3 0
2 years ago
A substance placed in a container has a fixed volume and takes up the shape of the container. In which state does this substance
Tems11 [23]
The substance should be in liquid state.

First, it takes up space in the container, which leads to that it shouldn't be a solid, because solid doesn't change its shape easily.

Second, it has a fixed volume, it's difficult to compress the substance, therefore it shouldn't be gas too, as gas can be compressed easily.

Therefore we're left with liquid. And both of these given properties fits the property of liquid.
6 0
3 years ago
In a unimolecular reaction with twice as much starting material as product at equilibrium, what is the value of Keq? Is ΔG o pos
lubasha [3.4K]

Answer : The value of K_{eq} is, 0.5 and \Delta G= positive.

Explanation :

The unimolecular reaction is:

A\rightarrow B

In unimolecular reaction, the starting material is 2 times to the product.

A=2B      .........(1)

As we know that:

K_{eq}=\frac{B}{A}     ...........(2)

Now substitute equation 1 in 2, we get:

K_{eq}=\frac{\frac{A}{2}}{A}

K_{eq}=0.5

Now we have to calculate the value of \Delta G^o at 298 K.

\Delta G^o=-RT\ln K_{eq}

where,

\Delta G^o = standard Gibbs free energy = ?

R = gas constant = 8.314 J/mol.K

T = temperature = 298 K

K_{eq} = equilibrium constant = 0.5

Now put all the given values on the above formula, we get:

\Delta G^o=-(8.314J/mol.K)\times (298K)\ln (0.5)

\Delta G^o=1717.32J/mol

Thus, the value of \Delta G^o at 298 K is, 1717.32 J/mol

As we know that:

\Delta G= +ve, reaction is non spontaneous

\Delta G= -ve, reaction is spontaneous

\Delta G= 0, reaction is in equilibrium

Thus, the \Delta G= +ve. So, the reaction is non spontaneous.

8 0
3 years ago
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