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Neko [114]
3 years ago
8

Rocks are classified as sedimentary, metamorphic, or igneous on the basis of

Chemistry
2 answers:
oee [108]3 years ago
7 0
The answer is b. way the rocks were formed.
olganol [36]3 years ago
7 0
The answer is B hope it correct cause I need more information
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Gustave-Gaspard Coriolanus described this type of energy
Paha777 [63]
I believe it’s Chemical energy but please correct me if i’m wrong
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3 years ago
Use the information from the diagram to calculate the enthalpy of combustion for methane. (HELP ASAPPP!!)
Blizzard [7]

Answer:

where is the diagram sisters

6 0
3 years ago
How many moles of Au2S3 is required to form 56 grams of H2S at STP?
Law Incorporation [45]

Answer:

0.55 mol Au₂S₃

Explanation:

Normally, we would need a balanced equation with masses, moles, and molar masses, but we can get by with a partial equation, if the S atoms are balanced.

1. Gather all the information in one place:

M_r:                          34.08

          Au₂S₃ + … ⟶ 3H₂S + …  

m/g:                             56  

2. Calculate the moles of H₂S

Moles of H₂S = 56 g H₂S × (34.08 g H₂S/1 mol H₂S)

                      = 1.64 mol H₂S

3. Calculate the moles of Au₂S₃

The molar ratio is 1 mol Au₂S₃/3 mol H₂S.

Moles of Au₂S₃ = 1.64 mol H₂S × (1 mol Au₂S₃/3 mol H₂S)

                         = 0.55 mol Au₂S₃

7 0
4 years ago
A flexible container at an initial volume of 6.13 L contains 2.51 mol of gas. More gas is then added to the container until it r
aleksley [76]

Answer:

2.12 moles of gas were added.

Explanation:

We can solve this problem by using<em> Avogadro's law</em>, which states that at constant temperature and pressure:

  • V₁n₂=V₂n₁

Where in this case:

  • V₁ = 6.13 L
  • n₂ = ?
  • V₂ = 11.3 L
  • n₁ = 2.51 mol

We <u>input the data</u>:

  • 6.13 L * n₂ = 11.3 L * 2.51 mol
  • n₂ = 4.63

As <em>4.63 moles is the final number of moles</em>, the number of moles added is:

  • 4.63 - 2.51 = 2.12 moles
5 0
3 years ago
A particular substance has a measured solubility in water of 3.6g/1.0L. How much of the substance can be dissolved in 650 L of w
harkovskaia [24]
I believe the correct answer is 2340g of a particular substance will be dissolved in 650 L of H2O. Hope I was helpful in some way. Thanks. Peace.
5 0
4 years ago
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