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Neko [114]
3 years ago
8

Rocks are classified as sedimentary, metamorphic, or igneous on the basis of

Chemistry
2 answers:
oee [108]3 years ago
7 0
The answer is b. way the rocks were formed.
olganol [36]3 years ago
7 0
The answer is B hope it correct cause I need more information
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. Which groups are identical in all amino acids? (Points : 1)
Murrr4er [49]
The answer is

<span>
only carboxyl groups (=C=OO-</span>
5 0
3 years ago
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how many mL of a 3.5 M sodium hydroxide will be needed to neutralize 15mL of a 4.3 M hydrochloric acid solution?
kobusy [5.1K]
Step 1 : write a valanced equation..
NaOH + HCl 》NaCl + H2O

Step 2 : find the number of mole of HCl..
1000 ml ..contains 4.3 mole
15ml... (4.3÷1000)×15 =...

Stem 3 : use mole ratio....
HCl : NaOH
1 : 1
So mole is same as calculated above...

Step 4 :
3.5 mole of NaOH is in 1000ml
(4.3÷1000)×15 mole is in ....


Do the calculation
6 0
3 years ago
What is the empiracle formula of amylose?
Jlenok [28]

Answer:

(C6H10O5)n

Explanation:

8 0
3 years ago
Instead of 6 M NaOH being added to the solution, 6 M HCl is added. How will this affect the test for the presence of ammonium io
Lera25 [3.4K]

Answer:

Ammonia gas(an alkaline gas with characteristics of choking or irritating smell) is not liberated when 6mole of HCl is added to the solution instead of 6mole of NaOH, to test for the presence of ammonium ion in the solution

Explanation:

As expected, when testing for ammonium ion in a solution (precisely ammonium salt solution), Sodium Hydroxide (NaOH) is required as the test reagent.

When NaOH is added to the solution, A gas with characteristics of choking or irritating smell is liberated.

This gas turn red litmus paper blue.

This liberated gas is an alkaline gas, which is confirmed as an ammonia gas(NH3).

If HCl is added instead of NaOH, the ammonia gas will not be liberated, which indicates that the test reagent used is wrong.

3 0
3 years ago
In the compound iodine heptafluoride: (hints: write out the molecular formula of this compound before answering the question. Al
Aloiza [94]

In the compound iodine heptafluoride: (hints: write out the molecular formula of this compound before answering the question. Also be sure you clearly understand the concepts of charge, oxidation numbers, how to determine charge and oxidation numbers, and - most important of all! - the similarities and the differences between charges and oxidation numbers)

<u>Each fluorine atom has a charge of 1</u>

<h3>What is iodine heptafluoride?</h3>

The interhalogen compound iodine heptafluoride, often known as iodine(VII) fluoride or iodine fluoride, has the chemical formula IF7.   As anticipated by VSEPR theory, it exhibits a unique pentagonal bipyramidal structure.  The molecule is capable of undergoing the Bartell process, a pseudorotational rearrangement that is similar to the Berry mechanism but for a heptacoordinated system.  It produces colorless crystals that melt at 4.5 °C and have a very narrow liquid range with a boiling point of 4.77 °C. The dense mist has an unpleasant, musty smell. The molecule is symmetrical with D5h. suggestion

To learn more about iodine heptafluoride from the given link:

brainly.com/question/28200374

#SPJ4

7 0
1 year ago
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