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svp [43]
2 years ago
11

How would one make a 2 M solution of a compound?

Chemistry
2 answers:
Sati [7]2 years ago
5 0

Answer:

B. By dissolving 2 moles of the compound in 1 L of water.

DiKsa [7]2 years ago
5 0

Answer:

<em>b</em>

Explanation:

<em>a pe x :)</em>

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List the number of
rjkz [21]

Answer:

beryllium: 2 valence electrons

nitrogen: 5  valence electrons

oxygen: 6 valence electrons

fluorine: 7  valence electrons

magnesium: 2+ valence electrons

phosphorus: 5 valence electrons

sulfur: 6 valence electrons

chlorine: 7  valence electrons

Explanation:

6 0
2 years ago
You have prepared a saturated solution of x at 20∘c using 39.0 g of water. how much more solute can be dissolved if the temperat
AleksAgata [21]

for 39g water solute dissolved at 20C = solubility ( g/ 100 g H2O ) × mass of water = ( 11g / 100g H2O ) × 39g H2O = 4.29 g

amount of solute dissolved at 30 C =

               =  23 / 100 * 39 = 8.97 g

Amount of extra solute dissolved = 8.97 - 4.29 = 4.7 g

3 0
3 years ago
What are the three common fossil fuels?
JulsSmile [24]
Coal, oil, and natural gas are the 3 common fossil fuels
6 0
3 years ago
R is the midpoint of FG.<br><br> FR = 26 find RG
vichka [17]

Answer:

52

Explanation:

This is because if R is the midpoint of FRG, FR is half of FRG, so basically all you do it multiply by 2 to get the FRG

7 0
3 years ago
A solution is made by combining 500 mL of 0.10 M HF (Ka=7.2 x 10^-4) with 300 mL of 0.15 M NaF. What is the pH of the resulting
n200080 [17]

Answer:

b) 3.10

Explanation:

HF ⇄ H + + F

Using Henderson-Hasselbalch Equation:

pH = pKa + log [A-]/[HA].

Where;

pKa = Dissociation constant = -log Ka

Hence, pKa of HF = -log 7.2 x 10^-4 = 3.14266

[A-] = concentration of conjugate base after dissociation = moles of base/total volume

          = 0.15 x 0.3/0.8

               = 0.05625 M

[HA] = concentration of the acid = moles of acid/total volume

             = 0.10 x 0.5/0.8

                    = 0.0625 M

Note: <em>Total volume = 500 + 300 = 800 mL = 0.8 dm3</em>

pH = 3.14266 + log [0.05625/0.0625]

      = 3.14267 + (-0.04575749056)

           = 3.09691250944

<em>From all the available options below:</em>

<em>a) 2.97 </em>

<em>b) 3.10 </em>

<em>c) 3.19 </em>

<em>d) 3.22 </em>

<em>e) 3.32</em>

The correct option is b.

4 0
3 years ago
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