Answer:
Explanation:
2 NO2(g) ⇄ N2O4(g)
Adding Argon to this reaction will have NO effect. Catalysts nor inert gases have an affect on equilibrium conditions.
Only changes in concentration, temperature conditions and pressure-volume conditions (unless both sides have equal molar volumes) will affect the equilibria.
NH4OH(aq) ⇄ NH3(g) + H2O(l)
Removing ammonia from reaction equilibrium causes the reaction to shift right to replace removed ammonia. => Think of the reaction as being on a seesaw => removing ammonia from the product side tilts the seesaw left causing the NH₄OH to decompose and deliver more NH₃ and H₂O to the product side to increase weight on that side and level the seesaw. :-)
<u>Answer:</u> The value of 
for the given reaction is 0.224
<u>Explanation:</u>
For the given chemical equation:
The expression of for given equation follows:
![K_c=\frac{[H_2][I_2]}{[HI]^2}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BH_2%5D%5BI_2%5D%7D%7B%5BHI%5D%5E2%7D)
We are given:
![[HI]_{eq}=0.85M](https://tex.z-dn.net/?f=%5BHI%5D_%7Beq%7D%3D0.85M)
![[H_2]_{eq}=0.27M](https://tex.z-dn.net/?f=%5BH_2%5D_%7Beq%7D%3D0.27M)
![[I_2]_{eq}=0.60M](https://tex.z-dn.net/?f=%5BI_2%5D_%7Beq%7D%3D0.60M)
Putting values in above expression, we get:
Hence, the value of for the given reaction is 0.224
Answer:
element
A pure substance is matter that is uniform throughout and has consistent properties. All matter is made up of very small particles called atoms. Atoms are the building blocks of all matter. When a substance contains only one type of atom, it is called an element.
The equation described by the kb value is 5.21 x 
.
The potential of Hydrogen is what pH is formally known as. The negative logarithm of the concentration of H+ ions is known as pH. Thus, the definition of pH as the amount of hydrogen is provided. The hydrogen ion concentration in a solution is described by the pH scale, which also serves as a gauge for the solution's acidity or basicity.
Assuming PO₄³⁻ (the phosphate anion).
PO₄³- + H₂O ==> HPO₄²⁻ + OH⁻
Kb = [HPO₄²⁻][OH⁻] / [PO₄³⁻]
We can find the [OH⁻] from the pH of 12.70.
pH + pOH = 14
14.0 - 12.7 = 1.3 = pOH
[OH] = 1x
[OH-] = 5.0x
M
[HPO₄²⁻] = 5.0x M
Kb = (5.0x)2 / 0.48
= 2.5x / 0.48
Kb = 5.21 x
Learn more about pH here:
brainly.com/question/8758541
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Answer:
CaCO3----------CaO+CO2
(40g+12g+16g×3) of CaCO3 produce (40g+16g) of CaO
100g of CaCO3 -----------------56g of CaO
20g of CaCO3-------------------x grams of CaO
x=(20g×56g)÷100g
x=1120gg÷100g
x=11.2g of CaO
Therefore, 11.2grams of CaO from 20grams of CaCO3
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