All the positive charge of an atom is contained in the nucleus, and originates from the protons. Neutrons are neutrally-charged. Electrons, which are negatively-charged, are located outside of the nucleus.
Onization energy is the energy required to lose an electron and form an ion. The stronger is the attraction of the atom and the electron the higher the ionization energy, and the weaker is the attraction of the atom and the electron the higher the ionization energy. This leads to a clear trend in the periodic table. Given that the larger the atom the weaker the attraction of the atom to the valence electrons, the easier they will be released, and the lower the ionization energy. This is, as you go downward in a group, the ionization energy decreases. So, the element at the top of the group will exhibit the largest ionization energy. <span>Therefore, the answer is that of the four elements of group 7A, fluorine will have the largest first ionization energy.</span>
Answer:
9.14moles
Explanation:
Given parameters:
Number of atoms of butane = 5.5 x 10²⁴atoms
Unknown:
Number of moles = ?
Solution:
To solve this problem, we must understand that a mole of any substance contains the Avogadro's number of particles.
6.02 x 10²³ atoms makes up 1 mole of an atom
5.5 x 10²⁴ atoms will contain = 
= 9.14moles
