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3 years ago

Do u ever fell like u ani't good enough for anybody

Chemistry

2 answers:

rjkz [21]3 years ago

3 0

Answer:

Hello

Explanation:

tbh YES and it sucks bc ppl treat u like trash, but don't let that get into ur head just be you, you'll find someone who treats u as if u were literally a goddess, keep ur head up and dont worry.

your welcome! ^^

Aloiza [94]3 years ago

3 0

✧･ﾟ: *✧･ﾟ:* hello there *:･ﾟ✧*:･ﾟ✧

the answer is down below

༶•┈┈⛧┈♛ ♛┈⛧┈┈┈┈⛧┈♛ ♛┈⛧┈┈┈┈⛧┈♛

yeah :(

i ain't good for anybody

༶•┈┈⛧┈♛ ♛┈⛧┈┈┈┈⛧┈♛ ♛┈⛧┈┈┈┈⛧┈♛

¯\_(ツ)_/¯

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2 NaOH (s) + CO2(g) → Na2CO3 (s) + H20 (I)

Paha777 [63]

<h3>Answer:</h3>

16.7 g H₂O

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

<u>Chemistry</u>

<u>Stoichiometry</u>

Reading a Periodic Table
Using Dimensional Analysis

<h3>Explanation:</h3>

<u>Step 1: Define</u>

[RxN - Balanced] 2NaOH (s) + CO₂ (g) → Na₂CO₃ (s) + H₂O (l)

[Given] 1.85 mol NaOH

<u>Step 2: Identify Conversions</u>

[RxN] 2 mol NaOH → 1 mol H₂O

Molar Mass of H - 1.01 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of H₂O - 2(1.01) + 16.00 = 18.02 g/mol

<u>Step 3: Stoichiometry</u>

Set up: $\displaystyle 1.85 \ mol \ NaOH(\frac{1 \ mol \ H_2O}{2 \ mol \ NaOH})(\frac{18.02 \ g \ H_2O}{1 \ mol \ H_2O})$
Multiply/Divide: $\displaystyle 16.6685 \ g \ H_2O$

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

16.6685 g H₂O ≈ 16.7 g H₂O

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