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boyakko [2]
3 years ago
14

I really need help with this, someone help me please.

Chemistry
1 answer:
Pepsi [2]3 years ago
6 0
Its C. It has to be equivalent to the number divided or multiplied by 5.
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A student was holding a metal rod to a candle flame. After a while he noticed that his hand was getting hot.
ArbitrLikvidat [17]

Answer:

Conduction

Explanation:

Conduction is when energy directly travels through a solid to get from one point to another.

4 0
3 years ago
A student performed a serial dilution on a stock solution of 1.33 M NaOH. A 1.0 mL aliquot of the stock NaOH (ms) was added to 9
serg [7]

Answer:

The correct answer is 1.33 x 10⁻⁵ M

Explanation:

The concentration of the stock solution is: C= 1.33 M

In the first dilution, the student added 1 ml of stock solution to 9 ml of water. The total volume of the solution is 1 ml + 9 ml = 10 ml. So, the first diluted concentration is:

C₁= 1.33 M x 1 ml/10 ml = 1.33 M x 1/10 = 0.133 M

The second dilution is performed on C₁. The student added 1 ml of 0.133 M solution to 9 ml of water. Again, the total volume is 1 ml + 9 ml = 10 ml. The second diluted concentration is:

C₂= 0.133 M x 1 ml/10 ml = 0.133 M x 1/10= 0.0133 M

Since the student repeated the same dilution process 3 times more (for a total of 5 times), we have to multiply 5 times the initial concentration by the factor 1/10:

Final concentration = initial concentration x 1/10 x 1/10 x 1/10 x 1/10 x 1/10

                                = initial concentration x (1/10)⁵

                                = 1.33 M x 1 x 10⁻⁵

                                = 1.33 x 10⁻⁵ M

3 0
3 years ago
The MO diagram of CN is similar to N2. Based on the molecular orbital energy-level diagram of CN, which of the following stateme
liubo4ka [24]

Answer:

Nitrogen molecule (N2)

The electronic configuration of nitrogen (Z=7) = 1s2 2s2 2px12py12pz1.

The total number of electrons present in the nitrogen molecule (N2) is 14.

In order to maximize energy, these 14 electrons can be accommodated in the different molecular orbitals.

N2: KK'(σ2s)2 (σ*2s)2 (π2Px)2 (π2py)2 (σ2pz)2

Here (σ1s)2 (σ*1s)2 part of the configuration is abbreviated as KK’, which denotes the K shells of the two atoms. In calculating bond order, we can ignore KK’, as it includes two bonding and two antibonding electrons.

The bond order of N2can be calculated as follows:

Here, Nb = 10 and Na = 4

Bond order = (Nb−Na) /2

B.O = (10−4)/2

B.O = 3

So your answer should be C3.

6 0
3 years ago
noble gases, such as argon and neon, are known for being extremely non-reactive. neon and argon are non-reactive because they
nadezda [96]
They have a complete electronic configuration .their P shell is p6 therefore cannot gain or loose electron.
4 0
3 years ago
Given: N2 + 3Cl2 → 2NCl3, ΔH = 464 kJ/mol Use the given bond energies and the periodic table to calculate the energy change in t
guapka [62]

The given chemical reaction is:

N_{2}+3Cl_{2}-->2NCl_{3}

ΔH^{0}_{reaction}=∑BE(reactants)-∑BE(products)

                 = {(941 kJ/mol) + (3 * 242 kJ/mol)} -[{2*(3*200 kJ/mol)}]

                     = 467 kJ/mol

Calculating the change in heat when 85.3 g chlorine reacts in the above reaction:

Moles of chlorine = 85.3 g Cl_{2}* \frac{1 mol Cl_{2}} {70.91 g Cl_{2}  }

                             = 1.20 mol Cl_{2}

Heat change when 1.20 mol chlorine reacts

                             = 1.20 mol * \frac{467kJ}{mol} =560.4 kJ

6 0
3 years ago
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