12, 2, 4, and 7. The coefficients in the expression 12xy³+2x⁵y+4x⁵y²+7x⁵y are 12, 2, 4, and 7.
In order to solve this problem we have to know that the coefficients is a factor linked to a monomial. For example, the first monomial of the equation is 12xy³ the coeffcient of xy³ is 12.
Answer:
Step-by-step explanation:
-2x + 3 = 0
-2x = -3
x = 3/2
-x^2 + 2x + 3 = (-3/2)^2 + 2 × 3/2 + 3
= 9/4 + 3 + 3
= 9/4 + 6
= 33/4
Hope this helps
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Tan ( a + b ) = [ tan a + tan b ] / [ 1 - (tan a)*(tan b) ];
let be a = 2x and b = x;
=> tan 3x = [ tan 2x + tan x ] / [ 1 - (tan 2x)*(tan x) ] => (tan 3x)*[ 1 - (tan 2x)*(tan x) ] =
tan 2x + tan x => tan3x - tan 3xtan 2xtanx = tan 2x + tan x => <span> tan 3x−tan 2x−tanx = tan 3xtan 2xtanx.</span><span />
Answer:
Step-by-step explanation:
if you need to evaluate the expression:
multiply 2 with the parenthesis
12e-6f-8
