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emmasim [6.3K]
2 years ago
14

Hey Boo faces what is 0.38 × 5 × (1/20) × 3 × (−8)

Mathematics
1 answer:
GarryVolchara [31]2 years ago
6 0

Answer:

-2.28

Step-by-step explanation:

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Answer this for 20 points
Setler79 [48]
Second one.

6% is 0.06
4 0
1 year ago
Jose is working two summer jobs, making $10 per hour washing cars and $9 per hour walking dogs. Last week Jose worked a total of
Setler [38]

Answer:

x+y =13

10x + 9y =122

Step-by-step explanation:

Hi, to answer this question we have to write a system of equations:

The sum of the hours he worked washing cars (x) and the hours he worked walking dogs(y) will be equal to the total hours worked (13)

  • x+y =13

For the second equation the product of the number of hours he worked washing cars(x) and the price per hour ($10) plus the product of the number of hours he worked walking dogs (y) and the price per hour ($9) will be equal to the total amount earned (122)-

  • 10x + 9y =122

So, the system of equations is:

  • x+y =13
  • 10x + 9y =122

Where:

x: number of hours Jose worked washing cars

y: number of hours Jose worked walking dogs  

7 0
3 years ago
Read 2 more answers
Consider the following graph of two functions,S(1) + 8(2)Step 1 of 2: Finds (1) + 8(2)Enable Zoom/Pan8(x) = x2 - 2x - 1S(x) = -x
kumpel [21]

.Given:

\begin{gathered} f(x)=-x+1 \\ g(x)=x^2-2x-1 \end{gathered}

ToDetermine: The value of

f(1)+g(2)

Solution

\begin{gathered} f(x)=-x+1 \\ f(1)=-1+1 \\ f(1)=0 \end{gathered}\begin{gathered} g(x)=x^2-2x-1 \\ g(2)=(2)^2-2(2)-1 \\ g(2)=4-4-1 \\ g(2)=-1 \\ f(1)+g(2)=0+(-1) \\ f(1)+g(2)=-1 \end{gathered}

Hence, f(1) + g(2) = -1

3 0
1 year ago
If a line contains the point (0, -1) and has a slope if 2, then which if the following points also lies on the line? (2, 1), (1,
Neko [114]
(1, 1) the slope is 2 and slopes can be read the easiest when expressed as a fraction (2/1) when the numerator (2) expresses how many digits you move the point up and the denominator (1) expresses how many points you move right
5 0
2 years ago
Iodine-125 has a half-life of about 60 days. How many milligrams of a 1000 mg sample will remain after 240 days?
Tomtit [17]

240 days is 4 times the half-life, which means that a sample of 1000 mg will decay to

\dfrac{1000}{2^4}=\dfrac{125}2=62.5\,\mathrm{mg}

after 240 days.

3 0
2 years ago
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