Answer:
A
Step-by-step explanation:
yw
For cos(2x) * (2cos(x) + 1) = 0, use the double angle identity for cos(2x), which is cos^2 x - sin^2 x = cos^2 x - (1-cos^2) = 2cos^2 x - 1.
So we have (2cos^2 x - 1)(2cos x + 1) = 0. So 2cos^2 x -1 = 0 or x = 0 and 2pi.
For 2sec^2 x + tan^2 x - 3 = 0, use the identity sec^2 x = tan^2 x + 1, so we have
2(tan^2 x + 1) + tan^2 x - 3 = 0 or
<span>2tan^2 x + tan^2 x - 1 = 0 or
</span>3 tan^2 x = 1.
So x = pi/2, pi/2 + pi = 3pi/2.
1. m = (y2 - y1) / (x2 - x1)
2. negative
3. y = 2
4. 0 slope
5. line A has steepest slope
6. (5,5)(-5,-1)...slope = -6/-10 = 3/5
7. Line B has a slope of -5
8. (1989,3)(1999,5.5) = 2.50/10 = 0.25
9. not sure
10. -1/4 inches per month
