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Jet001 [13]
3 years ago
11

Select the correct answer from each drop-down menu The rock cycle

Chemistry
2 answers:
MaRussiya [10]3 years ago
5 0

This makes no sence. Please put the picture up for us to answer. Thanks!

Alexxandr [17]3 years ago
4 0

Answer:

The picture?

Explanation:

Please the picture

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Which term is best defined as heat transfer that occurs when warm particles move in currents? A. evaporation B. convection C. co
baherus [9]
<span>The answer is B. Convection occurs when hot/warm water rise to the top and the cold water  goes to the bottom in a vessel. This is because hot/warm water is less dense than cold water. Additionally, convection currents are well perceptible in air and water and fluid substances that are poor conductors of heat</span>
8 0
4 years ago
Calculate the ph at the equivalence point for the titration of 0.230 m methylamine (ch3nh2) with 0.230 m hcl. the kb of methylam
Vlad1618 [11]

Answer: The pH at the equivalence point for the titration will be 0.65.

Solution:

Let the concentration of [OH^-] be x

Initial concentration of [CH3NH_2], c = 0.230 M

        CH_3NH_2+H_2O\rightleftharpoons CH_3NH_3^++OH^-

at eq'm  c-x                         x                    x

Expression of K_b:

K_b=\frac{[CH_3NH_3^+][+OH^-]}{[CH_3NH_2]}=\frac{x\times x}{c-x}=\frac{x^2}{c-x}

Since ,methyl-amine is a weak base,c>>x so c-x\approx c.

K_b=\frac{x^2}{c}=5.0\times 10^{-4}=\frac{x^2}{0.230 M}

Solving for x, we get:

x=1.07\times 10^{-2} M

Given, HCl with 0.230 M , it dissociates fully in water which means [H^+] = 0.230 M

[OH^-]=[H^+] will result in neutral solution, since [OH^-]

Remaining [H^+] after neutralizing [OH^-]ions

[H^+]_{\text{left in solution}}=[H^+]-[OH^-]=0.230-1.07\times 10^{-2}=0.2193 M

pH=-log{[H^+]_{\text{left in solution}}=-log(0.2193)=0.65

The pH at the equivalence point for the titration will be 0.65.

8 0
4 years ago
How many moles are in 3.45 g of Na2O?Round your answer to three significant
Neporo4naja [7]

Answer: There are 0.056 moles present in 3.45 g of Na_{2}O.

Explanation:

Given : Mass = 3.45 g

Moles is the mass of substance divided by its molar mass.

Hence, moles of Na_{2}O (molar mass = 61.98 g/mol) is as follows.

Moles = \frac{mass}{molar mass}\\= \frac{3.45 g}{61.98 g/mol}\\= 0.056 mol

Thus, we can conclude that there are 0.056 moles present in 3.45 g of Na_{2}O.

6 0
3 years ago
14. Explain, in terms of ions, why a 10.0-milliliter sample of 0.10 M NH4Cl(aq) is a poorer conductor of
Licemer1 [7]
Ionic compounds conduct electricity when dissolved in water, because the free-floating ions can carry charge. The more ions you have, the more readily the solution will carry that charge. 10.0 mL of 0.10 M NH4Cl has only 0.001 mol of NH4+ and 0.001 mol of Cl-, whereas 10.0 mL of 0.30 NH4Cl has 0.003 mol of NH4+ and 0.003 mol of Cl-. The 0.10 M sample is a poorer conducted of electricity because it has less ions in solution.
3 0
3 years ago
Convert 100mL to L. Show your work to receive full credit.
Ilya [14]

Answer:

100 ml = 0.1 L

I divided 100 by 1000 because 1000ml = 1L

3 0
3 years ago
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