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pickupchik [31]

3 years ago

14

Compare and contrast of cotton balls and pine cone

1 answer:

Alex3 years ago

3 0

<span>Cotton balls and pine cones are similar in that they both grow on plants and they contain the seeds of that plant. However, that is where the similarities end. By sight and feel alone, cotton balls and pine cones are vastly different. Cotton balls are soft and light, while pine cones have the potential to be a little dry and pri.ckly and have a bit of heft to them.</span>

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If a block weighs 125 grams and it has a volume of 5 mL, what is it's density?

Licemer1 [7]

The answer is 5 if u multiple

4 0

3 years ago

What is an example of a base? carbonic acid sodium carbonate sodium hydroxide hydrochloric acid

Zielflug [23.3K]

Answer:

The answer is sodium hydroxide.

Hope this helps.

3 0

3 years ago

The density of magnesium is 1.7 g/cm3, and the density of iron is 7.9 g/cm3. Consider a block of iron with a mass of 819 g. What

BigorU [14]

Answer:

mass of Mg=0.016g

Explanation:

P(Mg)=1.7g/cm³

P(Fe)=7.9g/cm³

m(Fe)=819g

P(Fe)=m(Fe)/v(Fe)

7.9=819/v(Fe)

v(Fe)=0.0096cm³

since v(Mg)=v(Fe)

=0.0096cm³

P(Mg)=m(Mg) /v(Mg)

1.7=m(Mg)/0.0096

m(Mg) = 0.016g

8 0

3 years ago

You are trying to determine the specific heat of a metal. You heat the 97 g piece of metal to 100 °C and place it in a calorimet

Brut [27]

Answer : The specific heat of the metal is, $0.658J/g^oC$

Explanation :

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

$q_1=-q_2$

$m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)$

where,

$c_1$ = specific heat of metal = ?

$c_2$ = specific heat of water = $4.18J/g^oC$

$m_1$ = mass of metal = 97 g

$m_2$ = mass of water = 122 g

$T_f$ = final temperature of mixture = $28.9^oC$

$T_1$ = initial temperature of metal = $100^oC$

$T_2$ = initial temperature of water = $20.0^oC$

Now put all the given values in the above formula, we get

$97g\times c_1\times (28.9-100)^oC=-122g\times 4.18J/g^oC\times (28.9-20.0)^oC$

$c_1=0.658J/g^oC$

Therefore, the specific heat of the metal is, $0.658J/g^oC$

8 0

3 years ago

What comes last in the scientific method

azamat

Hypothesis

Therefore the last step in the scientific method is proposing a hypothesis or obtaining a conclusion

6 0

3 years ago

Read 2 more answers