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zalisa [80]
3 years ago
15

HELP IM ON A TIME LIMIT AND IDK THE ANSWER

Mathematics
1 answer:
aleksandrvk [35]3 years ago
4 0

Answer:

Check step-by-step explanation

Step-by-step explanation:

A = \frac{1}{2} d_{1}  d_{2}

to solve for d_{1}:

d_{1} = \frac{2A}{d_{2}}

to solve for d_{2}:

d_{2} = \frac{2A}{d_{1}}

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ThHow many people younger than 50 are playing bingo?e following histogram represents the ages of people who are playing bingo.
Hunter-Best [27]

Answer:

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Step-by-step explanation:

3 0
3 years ago
What is the value for x
algol [13]
Those are adjacent angles. They will equal 180 degrees since they both ly on the same straight line. Straight line= 180 degrees. 

10x-20+6x+8=180

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~kaikers
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3 years ago
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Suppose a large shipment of laser printers contained 18% defectives. If a sample of size 340 is selected, what is the probabilit
lukranit [14]

Answer:

The probability that the sample proportion will be greater than 13% is 0.99693.

Step-by-step explanation:

We are given that a large shipment of laser printers contained 18% defectives. A sample of size 340 is selected.

Let \hat p = <u><em>the sample proportion of defectives</em></u>.

The z-score probability distribution for the sample proportion is given by;

                         Z  =  \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n}}  }  ~ N(0,1)

where, p = population proportion of defective laser printers = 18%

            n = sample size = 340

Now, the probability that the sample proportion will be greater than 13% is given by = P(\hat p > 0.13)

         P(\hat p > 0.13) = P( \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n}}  } > \frac{0.13-0.18}{\sqrt{\frac{0.13(1-0.13)}{340}}  } ) = P(Z > -2.74) = P(Z < 2.74)

                                                                      = <u>0.99693</u>

The above probability is calculated by looking at the value of x = 2.74 in the  table which has an area of 0.99693.

7 0
2 years ago
Please answer fast ASAP I give brainliest
Aleks04 [339]

Answer:

6x +12

Step-by-step explanation:

5 0
3 years ago
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