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Vikentia [17]
4 years ago
12

A piece of stainless steel weighing 1.55 g absorbs 141 J of heat energy when its temperature increases by 178oC. What is the spe

cific heat of stainless steel?
Chemistry
2 answers:
V125BC [204]4 years ago
7 0

Answer:

= 0.551J/(g°C)

Explanation:

Specific heat is the amount of heat to required to raise the temperature of 1 gram substance to 1° C

The formula

C = q / m × ΔT ______ (1)

where ,

C = specific heat

q = heat

m = mass

ΔT = change in temperature

mass of the stainless steel is m = 1.55g

heat of the stainless steel is q = 141 J

the change in temperature is ΔT = 178°C

substitute all the value in the equation (1)

C = \frac{141}{1.55 \times 178 } \\\\= 0.511J /(g^\circ C)

Naya [18.7K]4 years ago
3 0

Answer: The answer is 38,901.9(J/g°C)

Explanation:

Step one: given

mass m =1.55g

Heat capacity c= 141 joules

Change in temperature ΔT=178°c

Step two:

Applying the formula

q=mcΔT

q=1.55*141*178

q=38,901.9(J/g°C)

Specific heat capacity is the amount of heat energy required to raise the temperature of a substance per unit of mass

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1) How many atoms are in 0.54 moles of Cu? show work ​
mario62 [17]
<h3>Answer:</h3>

3.3 × 10²³ atoms Cu

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Moles
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[Given] 0.54 moles Cu

[Solve] atoms Cu

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

  1. [DA] Set up:                                                                                                      \displaystyle 0.54 \ mol \ Cu(\frac{6.022 \cdot 10^{23} \ atoms \ Cu}{1 \ mol \ Cu})
  2. [DA] Multiply [Cancel out units]:                                                                     \displaystyle 3.25188 \cdot 10^{23} \ atoms \ Cu

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 2 sig figs.</em>

3.25188 × 10²³ atoms Cu ≈ 3.3 × 10²³ atoms Cu

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Explanation:

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