A piece of stainless steel weighing 1.55 g absorbs 141 J of heat energy when its temperature increases by 178oC. What is the spe
2 answers:
Answer:
= 0.551J/(g°C)
Explanation:
Specific heat is the amount of heat to required to raise the temperature of 1 gram substance to 1° C
The formula
C = q / m × ΔT ______ (1)
where ,
C = specific heat
q = heat
m = mass
ΔT = change in temperature
mass of the stainless steel is m = 1.55g
heat of the stainless steel is q = 141 J
the change in temperature is ΔT = 178°C
substitute all the value in the equation (1)
You might be interested in
Answer:
The molarity is 0.56
Explanation:
In a mixture, the chemical present in the greatest amount is called a solvent, while the other components are called solutes. Then, the molarity or molar concentration is the number of moles of solute per liter of solution.
In other words, molarity is the number of moles of solute that are dissolved in a given volume.
The Molarity of a solution is determined by:
Molarity is expressed in units ().
Then you must know the number of moles of Cu(NO₂)₂. For that it is necessary to know the molar mass. Being:
- Cu: 63.54 g/mol
- N: 14 g/mol
- O: 16 g/mol
the molar mass of Cu(NO₂)₂ is:
Cu(NO₂)₂= 63.54 g/mol + 2*(14 g/mol + 2* 16 g/mol)= 155.54 g/mol
Now the following rule of three applies: if 155.54 g are in 1 mole of the compound, 225 g in how many moles are they?
moles= 1.45
So you know:
- number of moles of solute= 1.45 moles
- volume=2.59 L
Replacing in the definition of molarity:
Molarity= 0.56
<u><em>The molarity is 0.56</em></u><u><em></em></u>
Answer:
Here's what I get
Explanation:
Assume the initial concentrations of H₂ and I₂ are 0.030 and 0.015 mol·L⁻¹, respectively.
We must calculate the initial concentration of HI.
1. We will need a chemical equation with concentrations, so let's gather all the information in one place.
H₂ + I₂ ⇌ 2HI
I/mol·L⁻¹: 0.30 0.15 x
2. Calculate the concentration of HI
3. Plot the initial points
The graph below shows the initial concentrations plotted on the vertical axis.
