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Vikentia [17]
3 years ago
12

A piece of stainless steel weighing 1.55 g absorbs 141 J of heat energy when its temperature increases by 178oC. What is the spe

cific heat of stainless steel?
Chemistry
2 answers:
V125BC [204]3 years ago
7 0

Answer:

= 0.551J/(g°C)

Explanation:

Specific heat is the amount of heat to required to raise the temperature of 1 gram substance to 1° C

The formula

C = q / m × ΔT ______ (1)

where ,

C = specific heat

q = heat

m = mass

ΔT = change in temperature

mass of the stainless steel is m = 1.55g

heat of the stainless steel is q = 141 J

the change in temperature is ΔT = 178°C

substitute all the value in the equation (1)

C = \frac{141}{1.55 \times 178 } \\\\= 0.511J /(g^\circ C)

Naya [18.7K]3 years ago
3 0

Answer: The answer is 38,901.9(J/g°C)

Explanation:

Step one: given

mass m =1.55g

Heat capacity c= 141 joules

Change in temperature ΔT=178°c

Step two:

Applying the formula

q=mcΔT

q=1.55*141*178

q=38,901.9(J/g°C)

Specific heat capacity is the amount of heat energy required to raise the temperature of a substance per unit of mass

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2 years ago
If 13 grams of copper sulfate is reacted with zinc how much of each product is produced?
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No. Of Moles of zinc = m/Ar

= 13/ 65.38 = 0.198 moles

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Explanation:

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For the reaction A + B + C → D + E, the initial reaction rate was measured for various initial concentrations of reactants. The
babymother [125]

Answer : The order of reaction with respect to A is, second order reaction.

The order of reaction with respect to B is, zero order reaction.

The order of reaction with respect to C is, first order reaction.

Explanation :

Rate law is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.

For the given chemical equation:

A+B+C\rightarrow D+E

Rate law expression for the reaction:

\text{Rate}=k[A]^a[B]^b[C]^c

where,

a = order with respect to A

b = order with respect to B

c = order with respect to C

Expression for rate law for first observation:

6.0\times 10^{-4}=k(0.20)^a(0.20)^b(0.20)^c ....(1)

Expression for rate law for second observation:

1.8\times 10^{-3}=k(0.20)^a(0.20)^b(0.60)^c ....(2)

Expression for rate law for third observation:

2.4\times 10^{-3}=k(0.40)^a(0.20)^b(0.20)^c ....(3)

Expression for rate law for fourth observation:

2.4\times 10^{-3}=k(0.40)^a(0.40)^b(0.20)^c ....(4)

Dividing 1 from 2, we get:

\frac{1.8\times 10^{-3}}{6.0\times 10^{-4}}=\frac{k(0.20)^a(0.20)^b(0.60)^c}{k(0.20)^a(0.20)^b(0.20)^c}\\\\3=3^c\\c=1

Dividing 1 from 3, we get:

\frac{2.4\times 10^{-3}}{6.0\times 10^{-4}}=\frac{k(0.40)^a(0.20)^b(0.20)^c}{k(0.20)^a(0.20)^b(0.20)^c}\\\\4=2^a\\a=2

Dividing 3 from 4, we get:

\frac{2.4\times 10^{-3}}{2.4\times 10^{-3}}=\frac{k(0.40)^a(0.40)^b(0.20)^c}{k(0.40)^a(0.20)^b(0.20)^c}\\\\1=2^b\\b=0

Thus, the rate law becomes:

\text{Rate}=k[A]^2[B]^0[C]^1

Thus,

The order of reaction with respect to A is, second order reaction.

The order of reaction with respect to B is, zero order reaction.

The order of reaction with respect to C is, first order reaction.

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