HELP ASAP WILL MARK BRAINLIEST

Mathematics

2 answers:

alexandr402 [8]3 years ago

5 0

Answer:

Step-by-step explanation:

Since each week the number of teams is increasing by a constant amount, the graph has a constant slope, and should be a line, and not any kind of exponential curve.

ira [324]3 years ago

3 0

Answer:

Graph A

Step-by-step explanation:

registering 6 teams weekly

y=6x- this is linear equation

Graph A is the correct answer,

the other graph is not a linear function

You might be interested in

I need help!!

netineya [11]

Answer:

2x +21

Step-by-step explanation:

$log_{5} {5}^{(2x - 9)} + log_{3} {729}^{5} \\ \\ = log_{5} {5}^{(2x - 9)} + log_{3} {( {3}^{6} )}^{5} \\ \\ = log_{5} {5}^{(2x - 9)} + log_{3} { {3}}^{6 \times 5} \\ \\ = log_{5} {5}^{(2x - 9)} + log_{3} { {3}}^{30} \\ \\ =(2x - 9) log_{5} {5} + 30 log_{3} { {3}} \\ \\ = (2x - 9).1 + 30(1 )\\ ( \because \: log_{a} { {a}} = 1) \\ \\ = 2x - 9 + 30 \\ \\ = 2x +21$

7 0

3 years ago

Plizz help me out on this oneee

Kobotan [32]

There are 30 students all together, and 4 of them are Freshman girls (Freshwomen ?). So the probability that one randomly chosen student is a Female Frosh is 4/30 = 2/15.

8 0

3 years ago

Suppose that birth weights are normally distributed with a mean of 3466 grams and a standard deviation of 546 grams. Babies weig

Anon25 [30]

Answer:

3.84% probability that it has a low birth weight

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 3466, \sigma = 546$