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son4ous [18]
3 years ago
9

Please help this is due in 3 hours!! #17

Mathematics
1 answer:
Westkost [7]3 years ago
4 0

Answer:

multiply 31.4x7.9 then add 9.5 to the answer to multiplication prob. Then add your answer in the first sentence. Then multiply 4.6 x 2 . I think that right,good luck : ) luck.

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If x*3=64, what is the value of x?
dusya [7]

Answer:

x = 21.3 repeating. so put the - on top of the 3 if you're writing it down

4 0
3 years ago
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The height of a triangle is half the length of its base. The area of the triangle is 12.25cm. Find the height
pentagon [3]
Answer:  The height of the triangle is:  " 3.5 cm " .
_______________________________________________________
<u>
Note</u>:
 The formula/equation for the area, "A" , of a triangle is:

           A = (1/2) * b * h  ;  or write as:  A = (b * h) / 2 ; 
_________________________________________________
 in which:   "A = area of the triangle" ; 
                  "b = base length" ; 
                  "h = "[perpendicular] height" ; 
_________________________________________________
     Given:  h = (b/2) ;
                  A = 12.25 cm²
{Note:  Let us assume that the given area was "12.25 cm² " .}. 
_________________________________________________
 We are to find the height, "h" ; 

The formula for the Area, "A", is:   A = (b * h) / 2 ; 

Let us rearrange the formula ;
 to isolate the "h" (height) on one side of the equation; 

→ Multiply EACH side of the equation by "2" ; to eliminate the "fraction" ; 

2*A = [ (b * h) / 2 ] * 2 ; 

   to get:   " 2A = b * h " ; 

↔    " b * h = 2A " ; 

Divide EACH SIDE of the equation by "b" ; to isolate "h" on one side of the equation: 

        →  (b * h) / b  = (2A) / b ; 

to get: 
  
        →   h  =  2A / b ; 

Since  "h = b/2" ; subtitute "b/2" for "h" ; 
 
Plug in:  "12.25 cm² " for "A" ;

       →  b/2  =  2A/b ;   →  Note:  " 2A/b = [2* (12.25 cm²) ] / b " ;

Note:  " 2* (12.25 cm²) = 24.5 cm² ; 

Rewrite as: 

       →  b/2  =  (24.5 cm²) / b ;
_____________________________________
Cross-multiply:   b*b = (24.5 cm²) *2 ; 

to get:   b² = 49 cm² ; 

Take the "positive square root" of each side of the equation" ; 
            to isolate "b" on one side of the equation ; & to solve for "b" ; 

             →  +√(b²)  =  +√(49 cm²) ; 

             →  b = 7 cm ; 

Now, we want to solve for "h" (the height) :
_________________________________________________________
             →  h = b / 2 = 7 cm / 2 = 3.5 cm ; 
_________________________________________________________
Answer:  The height of the triangle is:  " 3.5 cm <span>" .
</span>_________________________________________________________
6 0
3 years ago
FR.EE POINTS HAVE A GOOD DAY 100PTS :)
Law Incorporation [45]

Answer:

Thank u so much have a good day too

5 0
3 years ago
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What else would need to be congruent to show that AABC=A DEF by the
Pepsi [2]

Answer:

D. AC ≅ DF

Step-by-step explanation:

According to the AAS Theorem, two triangles are considered congruent to each other when two angles and a mon-included side of one triangle are congruent to two corresponding angles and a corresponding non-included side of the other.

Thus, in the diagram given:

<A and <B in ∆ABC are congruent to corresponding angles <D and <E in ∆DEF.

The only condition left to be met before we can conclude that both triangles are congruent by the AAS Theorem is for a mon-included side AC to be congruent to corresponding non-included side DF.

So, AC ≅ DF is what is needed to make both triangles congruent.

7 0
3 years ago
Just for fun ‍♀️<br> 5 + 5 • 5 - 5
garri49 [273]
5+5 = 10 5-5= 0 10× 0 = 0 answer is 0
8 0
3 years ago
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