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andrew11 [14]
2 years ago
14

How do i get the answer for the problem (15y−2)+(−17y+4)

Mathematics
2 answers:
marshall27 [118]2 years ago
8 0
-2y+2 combine like terms. this what your looking for?
Masja [62]2 years ago
7 0
FOIL 

Front term ( 15y) multiplied with the Last (4) then multiply the Front term (15y) with the Inside term (-17y). Now, multiply the other Inside term (-2) by the Last term (4) and the Inside term (-17).

Multiply each number by both of the other numbers in the other set of ( ).  
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aalyn [17]
The answer is x = 1/3

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Please help. I know it’s not the hardest, but I think I did something wrong when I solved it. Please include your work. Tysm! Pl
Alex73 [517]

1 Multiply both sides by

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(

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)

n+0.3=

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​

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2 Simplify

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(

n

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)

2

9

​

(n−3.2) to

9

(

n

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2

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n

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(

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2

n+0.3=

2

9(n−3.2)

​

3 Multiply both sides by

2

2.

2

n

+

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=

9

(

n

−

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)

2n+0.6=9(n−3.2)

4 Expand.

2

n

+

0.6

=

9

n

−

28.8

2n+0.6=9n−28.8

5 Subtract

2

n

2n from both sides.

0.6

=

9

n

−

28.8

−

2

n

0.6=9n−28.8−2n

6 Simplify

9

n

−

28.8

−

2

n

9n−28.8−2n to

7

n

−

28.8

7n−28.8.

0.6

=

7

n

−

28.8

0.6=7n−28.8

7 Add

28.8

28.8 to both sides.

0.6

+

28.8

=

7

n

0.6+28.8=7n

8 Simplify

0.6

+

28.8

0.6+28.8 to

29.4

29.4.

29.4

=

7

n

29.4=7n

9 Divide both sides by

7

7.

29.4

7

=

n

7

29.4

​

=n

10 Simplify

29.4

7

7

29.4

​

to

4.2

4.2.

4.2

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n

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11 Switch sides.

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4 0
2 years ago
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miskamm [114]
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4 0
3 years ago
the height of a ball dropped from a 160 foot building after t seconds is represented by h(t)=160-16t^2.how high will the ball be
alekssr [168]

Answer:

The height of the ball after 3 secs of dropping is 16 feet.

Step-by-step explanation:

Given:

height from which the ball is  dropped = 160 foot

Time = t seconds

Function h(t)=160-16t^2.

To Find:

High will the ball be after 3 seconds = ?

Solution:

Here the time ‘t’ is already given to us as 3 secs.

We also have the relationship between the height and time given to us in the question.

So, to find the height at which the ball will be 3 secs after dropping we have to insert 3 secs in palce of ‘t’ as follows:

h(3)=160-16(3)^2

h(3)=160-16 \times 9

h(3)=160-144

h(3)=16

Therefore, the height of the ball after 3 secs of dropping is 16 feet.

8 0
3 years ago
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