All categories

3 years ago

Keenan owns an ice cream store, Papa Smurf's Ice Cream, on Main Street.

Mathematics

1 answer:

Archy [21]3 years ago

6 0

Answer:

there's no picture

Step-by-step explanation:

You might be interested in

Please help me with these questions

Scrat [10]

3. Answer: y = 4

Step-by-step explanation:

Need to find the slope (m):

$\dfrac{y_2-y_1}{x_2-x_1}$

$\dfrac{4 - 4}{-3-1}$

= $\dfrac{0}{-4}$

= 0

Now input ONE of the points (1, 4) and the slope (m = 0) into the Point-Slope formula:

y - y₁ = m(x - x₁)

y - 4 = 0(x - 1)

y - 4 = 0

y = 4

********************************************************************

4. Answer: $\bold{y = \dfrac{2}{3}x + 3}$

Step-by-step explanation:

$y - y_1 = m(x - x_1)$

$y - 1 = \dfrac{2}{3}(x - (-3))$

$y - 1 = \dfrac{2}{3}(x + 3)$

$y - 1 = \dfrac{2}{3}x + 2$

$y = \dfrac{2}{3}x + 3$

3 0

3 years ago

Over the last three evenings, Diane received a total of 105 phone calls at the call center. The third evening, she received 4 ti

sergij07 [2.7K]

Answer:

Make an eqaution from here.
Let’s make evening 2 “x”

So the first evening has 9 less then the secon evening so…
x-9
Of course theres the second evening (x).

X-9+x
Then the third evening has 4 times as much as the second meeting so…
x-9+x+4x

And when solved, it has to equal 105.

So solve from here.
Combine like terms.

6x-9=105
Isolate

6x=114
x= 19

First evening is 9 less then 19, so 10.

The second evening was 19 calls.
The third evening was 4 times the second evening so, 19*4= 76

1st night = 10

2nd night= 19 calls
Thrid night= 76 calls

8 0

3 years ago

Pls help asap if square x = -7 ; then x = - 49

natima [27]

Should be false because -7 x -7 is not -49 it is 49

4 0

3 years ago

Solve for u -u + 114 = 262 PLEASE WITCHER3

AleksandrR [38]

Hi ;-)

$-u+114=262\\\\-u=262-114\\\\-u=148 \ \ /:(-1)\\\\\huge\boxed{u=-148}$

3 0

3 years ago

Read 2 more answers

A U.S. Travel Data Center survey of 500 adults found that 195 said they would take more vacations this year than last year. Cons

Lelechka [254]

Using the z-distribution, it is found that the 95% confidence interval for the true proportion of adults who said that they will travel more this year is (0.347, 0.433).

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which z is the z-score that has a p-value of $\frac{1+\alpha}{2}$ .

195 out of 500 people said they would take more vacations this year than last year, hence:

$n = 500, \pi = \frac{195}{500} = 0.39$

95% confidence level, hence $\alpha = 0.95$ , z is the value of Z that has a p-value of $\frac{1+0.95}{2} = 0.975$ , so $z = 1.96$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.39 - 1.96\sqrt{\frac{0.39(0.61)}{500}} = 0.347$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.39 + 1.96\sqrt{\frac{0.39(0.61)}{500}} = 0.433$

The 95% confidence interval for the true proportion of adults who said that they will travel more this year is (0.347, 0.433).

A similar problem is given at brainly.com/question/15850972

5 0

3 years ago