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klio [65]
3 years ago
9

.A 100.0-W lightbulb is 22 percent efficient. This means that 22 percent of the electrical energy is transformed to radiant ener

gy.
a. How many joules does the lightbulb transform into radiant energy each minute it is in operation?

b. How many joules of thermal energy does the lightbulb output each minute?
Physics
1 answer:
algol [13]3 years ago
6 0

Answer:

Explanation:

100 W bulb is using energy of 100 J in one second.

22 percent of the electrical energy is transformed to radiant energy.

a )

So , electrical energy is transformed to radiant energy per second

= 100 x .22 = 22 J

energy transformed in one minute = 22 x 60  J

= 1320 J

b )

electrical energy is transformed to heat  energy per second

= 100 x .78 = 78 J

energy transformed in one minute = 78 x 60  J

= 4680  J

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According to the law of conservation of matter, we know that the total number of atoms does not change in a chemical reaction an
iogann1982 [59]

Answer:

In a chemical reaction the total mass of all the substances taking part in the reaction remains the same. Also, the number of atoms in a reaction remains the same. Mass cannot be created or destroyed in a chemical reaction.

Explanation:

7 0
3 years ago
1. A step-up transformer increases 15.7V to 110V. What is the current in the secondary as compared to the primary? Assume 100 pe
Serjik [45]

1. I_2 = 0.14 I_1

Explanation:

We have:

V_1 = 15.7 V voltage in the primary coil

V_2 = 110 V voltage in the secondary coil

The efficiency of the transformer is 100%: this means that the power in the primary coil and in the secondary coil are equal

P_1 = P_2\\V_1 I_1 = V_2 I_2

where I1 and I2 are the currents in the two coils. Re-arranging the equation, we find

\frac{I_2}{I_1}=\frac{V_1}{V_2}=\frac{15.7 V}{110 V}=0.14

which means that the current in the secondary coil is 14% of the value of the current in the primary coil.

2. 5.7 V

We can solve the problem by using the transformer equation:

\frac{N_p}{N_s}=\frac{V_p}{V_s}

where:

Np = 400 is the number of turns in the primary coil

Ns = 19 is the number of turns in the secondary coil

Vp = 120 V is the voltage in the primary coil

Vs = ? is the voltage in the secondary coil

Re-arranging the formula and substituting the numbers, we find:

V_s = V_p \frac{N_s}{N_p}=(120 V)\frac{19}{400}=5.7 V

5 0
3 years ago
A substance did not change it's chemical nature in reaction which mostly likely describe the reaction
Ad libitum [116K]
If the substance doesn't change chemically, it is a physical reaction.
8 0
3 years ago
What number and type of hybrid orbital(s) form(s) when one p and one s atomic orbital mix?
Harrizon [31]

Two equivalent hybridized orbitals will form from the mixing of one s-orbital and one p-orbital, that is (sp) orbital.

<h3>What are orbitals?</h3>

Orbital is the place around nucleus where mostly the electrons are present. There are four types of orbitals are present, s, p, d, and f.

The orbitals that are formed by the mixing of these orbitals are called hybrid orbitals.

Thus, two equivalent hybridized orbitals will form from the mixing of one s-orbital and one p-orbital, that is (sp) orbital.

Learn more about orbitals

brainly.com/question/18914648

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3 0
2 years ago
A sound has a sound level of 30 dB. Its intensity is what multiple of the standard reference level for intensities?
arsen [322]
<h2>Answer:</h2>

1000th multiple of the standard reference level for intensities.

<h2>Explanation:</h2>

The sound intensity level (β), measured in decibels, of a sound with an intensity of I is defined as follows;

β = 10 log (I / I₀)       --------------------(i)

Where;

I₀ = reference intensity

Given from the question;

β = sound level = 30dB

Substitute this value into equation (i) as follows;

30 = 10 log (I / I₀)

Divide both sides by 3;

3 = log (I / I₀)

Take antilog of both sides;

10^(3) = (I / I₀)

1000 = I / I₀

Solve for I;

I = 1000I₀

Therefore the intensity of the sound is 1000 times the standard reference level for intensities (I₀)

7 0
3 years ago
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