Which way does the blue arrow on the earth point
1 answer:
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Answer:
20.4
Explanation:
To start doing this problem, first draw a free body diagram of the table. My teacher always tells us to do this, and I find that it is very helpful. I have attached a free body diagram to this answer- take a look at it.
First, let us see if Net force = MA. To do that, we need to determine whether the object is at equilibrium horizontally. For an object to be at equilibrium, it either needs to be moving at a constant velocity or not moving at all. Also, if an object is at equilibrium, there will not be any acceleration. But we know that there IS acceleration horizontally, so it cannot be in equilibrium. If it is not in equilibrium, we can use the formula ∑F= ma.
Let us determine the net force. Since the object is moving horizontally, we can ignore the weight and normal force, because they are vertical forces. The only horizontal forces we need to worry about are the applied force and force of friction.
Applied force = 1055 N (490 + 565)
Friction force= Unknown
To find the friction force, use the kinetic friction formula, Friction = μkN
μk is the coefficient, which the problem includes- it is 0.613.
N is the normal force, which we have to find.
*To find the normal force, we have to determine if the object is at equilibrium VERTICALLY. Since it has no acceleration vertically (it's not moving up/down), it is at equilibrium. Now, when an object is at equilibrium in one direction, it means that all the forces in that direction are equal. What are our vertical forces? Weight (mg) and Normal force (N). So it means that the Normal force is equal to the Weight.
Weight = mg = (40)(9.8) = 392 N
Normal force = 392 N
Now, plug it back into the formula (μkN): (0.613)(392) = 240.296 N
Friction = 240.296 N
Now that we know the friction, we can find the horizontal net force. Just subtract the friction force, 240.296 from the applied force, 1055 N
Horizontal Net Force: 814.704 N
Now that we know the net force, plug in the numbers for the formula
∑F= ma.
814.704 = (40.0)(a)
*Divide on both sides)
a = 20.3676 m/s^2
Round it to 3 significant figures, to get:
20.4
Answer: The students will determine the two fixed points of the thermometer:
Lower fixed point = 0 degree Celsius
Upper fixed point = 100 degree Celsius
Then divide the thermometer with equal intervals
The room temperature will be the point at which the themometric substance remains constant when rising from ice point.
Explanation:
Apparatus available:
Unmarked thermometer
250 cm3 glass beaker
crushed ice
water
heatproof mat
clamp, boss and stand
meter rule
Added apparatus
Bunsen burner
Stirrer
Method
The students will determine the two fixed points of the thermometer:
Lower fixed point = 0 degree Celsius
Upper fixed point = 100 degree Celsius
Then divide the thermometer with equal intervals
Procedures
Set up the apparatus of illustrated in the attached figure.
Immerse the unmarked thermometer into the ice in the beaker.
When the level indicated by the thermometric substance remains steady after some time, a mark will be made at that point. This mark will corresponds to the ice point (lower fixed point) and is assigned the value of 0 °C.
You may add little water and continue to stir gently.
The themometric substance will start to rise and stop when it reaches room temperature. Mark the point but do not assign any value
Place the beaker on bunsen burner and boil the water. The themometric substance will continue to rise and remain constant at upper fixed point
This mark will corresponds to the steam point (upper fixed point) and is assigned the value of 100 °C.
Divide between the lower fixed point and upper fixed point into equal intervals. Then you can see the value of room temperature.
