Which way does the blue arrow on the earth point

List 3 additional real world examples that show work being done.

Usimov [2.4K]

I am walking to the end of the room holding three textbooks.
Playing tug of war
Moving boxes to move out of your house

8 0

3 years ago

When the temperature of a metal cylinder is raised from 0.0°C to 110°C, its length increases by 0.22%. Find the percent change i

monitta

Volume of cylinder = pi*r*2*L

As, from the above formula,volume is directly proportional to length,
So, if we increase in length also increases in volume by 0.22%

we know

density=mass/volume

As, density is inversely proportional to volume it means increasing in volume decreases the density by 50.22%

8 0

3 years ago

Read 2 more answers

If the mass of a

mixer [17]

Answer:

The final acceleration becomes (1/3) of the initial acceleration.

Explanation:

The second law of motion gives the relationship between the net force, mass and the acceleration of an object. It is given by :

$F=ma$

m = mass

a = acceleration

According to given condition, if the mass of a sliding block is tripled while a constant net force is applied. We need to find how much does the acceleration decrease.

$a=\dfrac{F}{m}$

Let a' is the final acceleration,

$a'=\dfrac{F}{m'}$

m' = 3m

$a'=\dfrac{F}{3m}$

$a'=\dfrac{1}{3}\times \dfrac{F}{m}$

$a'=\dfrac{1}{3}\times a$

So, the final acceleration becomes (1/3) of the initial acceleration. Hence, this is the required solution.

5 0

3 years ago

The displacement vector from your house to the library is 520 m long, pointing 40 ∘ north of east.What are the x-component (x-ax

Alexeev081 [22]

Answer:

398.3 m, 334.2 m

Explanation:

The magnitude of the displacement vector is

v = 520 m

And its direction is

$\theta=40^{\circ}$

measured as north of east.

The x-component of this vector is given by:

$v_x = v_0 cos \theta = (520)cos 40^{\circ}=398.3 m$

While the y-component is given by

$v_y = v_0 sin \theta =(520)sin 40^{\circ}=334.2 m$

7 0

3 years ago

At time t1 = 2.00 s, the acceleration of a particle in counterclockwise circular motion is (7.00 m/s2)i hat + (6.00 m/s2)j. It m

Elina [12.6K]

Answer:

r = 3519.55 m

Explanation:

We know that the acceleration of a particle in a circular motion is directed towards the center of the circumference and has magnitude:

F = rω^2

Where r is the radius of the circumference and ω is the angular velocity.

From the two acceleration vectors we find that their magnitude is

√(7^2+6^2) = √85

Therefore:

√85 m/s^2= rω^2

Now we need to calculate the angular velocity to obtain the radius. Since t2-t1 = 3s is less than one period we can be sure that the angular velocity is equals to the angle traveled between this time divided by 3 s.

The angle with respect to the x-axis for the particle at t1 and t2 is:

$\theta 1 =\cos ^{-1}\left(\frac{7}{\sqrt{85}}\right)\\\theta 2 =\cos ^{-1}\left(\frac{6}{\sqrt{85}}\right)\\$

Therefore, the angular velocity ω is (in radians per second):

$\omega = \frac{\theta2 - \theta1}{3 s} = 0.0511813 \frac{1}{s}$

Therefore:

r = √85 / (0.0511813)^2 = 3519.55 m

4 0

3 years ago