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3 years ago

11

A vector quantity is the magnitude of a given quantity? True Or False

1 answer:

Anettt [7]3 years ago

6 0

Answer:

false

Explanation:

A vector quantity is the magnitude of a given quantity? True Or False

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In the aftermath of an intense earthquake, the earth as a whole "rings" with a period of 54 minutes.

lawyer [7]

The frequency of the oscillation in hertz is calculated to be 0.00031 Hz.

The frequency of a wave is defined as the number of cycles completed per second while the period refers to the time taken to complete a cycle. The frequency is the inverse of period.

So;

Period(T) = 54 minutes or 3240 seconds

Frequency (f) = T-1 = 1/T = 1/3240 seconds = 0.00031 Hz

Learn more: brainly.com/question/14588679

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2 years ago

An important difference between a universal and a split-phase motor is that the split-phase motor has A. two brushes attached to

olga nikolaevna [1]

An important difference between a universal and a split-phase motor is that the split-phase motor has

A. two brushes attached to the stator.

B. a single coil formed on the rotor.

<u>C. two windings on the stator. </u>

D. an armature with a commutator.

6 0

3 years ago

A camera, a drill, and a hand-squeeze flashlight use either a generator or a motor as a component. Identify which component each

muminat

A camera is a motor.

A drill is a motor.

A hand-squeeze flashlight is a generator.

Hope this helped :)

4 0

3 years ago

Read 2 more answers

As an object falls

Sidana [21]

As an object falls in response to gravitational force, its velocity increases
and its acceleration is unchanged. On Earth, its acceleration is 9.8 m/s².

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2 years ago

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An electron with velocity v = 1.0 ´ 106 m/s is sent between the plates of a capacitor where the electric field is E = 500 V/m. I

oksano4ka [1.4K]

Answer:

The deviation in path is $4.39 \times 10^{-3}$

Explanation:

Given:

Velocity $v = 1 \times 10^{6}$ $\frac{m}{s}$

Electric field $E = 500$ $\frac{V}{m}$

Distance $x = 1 \times 10^{-2}$ m

Mass of electron $m = 9.1 \times 10^{-31}$ kg

Charge of electron $q = 1.6 \times 10^{-19}$ C

Time taken to travel distance,

$t = \frac{x}{v}$

$t = \frac{1 \times 10^{-2} }{1 \times 10^{6} }$

$t = 10^{-8}$ sec

Acceleration is given by,

$F = qE$

$ma = qE$

$a = \frac{qE}{m}$

$a = \frac{1.6 \times 10^{-19} \times 500}{9.1 \times 10^{-31} }$

$a = 8.77 \times 10^{13}$ $\frac{m}{s^{2} }$

For finding the distance, we use kinematics equations.

$y = vt + \frac{1}{2} at^{2}$

Where $v = 0$ because here initial velocity zero

$y = \frac{1}{2} at^{2}$

$y = \frac{1}{2} \times 8.77 \times 10^{13 } \times (10^{-2} )^{2}$

$y = 4.39 \times 10^{-3}$ m

Therefore, the deviation in path is $4.39 \times 10^{-3}$

6 0

3 years ago