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4 years ago

A vector quantity is the magnitude of a given quantity? True Or False

Physics

1 answer:

Anettt [7]4 years ago

6 0

Answer:

false

Explanation:

A vector quantity is the magnitude of a given quantity? True Or False

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An astronaut circling the earth at an altitude of 400 km is horrified to discover that a cloud of space debris is moving in the

elena-14-01-66 [18.8K]

One of the essential concepts to solve this problem is the utilization of the equations of centripetal and gravitational force.

From them it will be possible to find the speed of the body with which the estimated time can be calculated through the kinematic equations of motion. At the same time for the calculation of this speed it is necessary to clarify that this will remain twice the ship, because as we know by relativity, when moving in the same magnitude but in the opposite direction, with respect to the ship the debris will be double speed.

By equilibrium the centrifugal force and the gravitational force are equal therefore

$F_c = F_g$

$\frac{mv^2_{orbit}}{r} = \frac{GMm}{r^2}$

Where

m = mass spacecraft

v = velocity

G = Gravitational Universal Constant

M = Mass of earth

$r \rightarrow R+h \Rightarrow$ Radius of earth and orbit

Re-arrange to find the velocity

$\frac{mv^2_{orbit}}{r} = \frac{GMm}{r^2}$

$\frac{v^2_{orbit}}{r} = \frac{GM}{r^2}$

$v^2_{orbit}=\frac{GM}{r}$

$v_{orbit} = \sqrt{\frac{GM}{r}}$

$v_{orbit} = \sqrt{\frac{GM}{R+h}}$

Replacing with our values we have

$v_{orbit} = \sqrt{\frac{(6.67*10^{-11})(5.98*10^{24})}{6.37*10^6+0.4*10^6}}$

$v_{orbit} = 7676m/s$

From the cinematic equations of motion we have to

$t = \frac{d}{2v_{orbit}} \rightarrow$ Remember that the speed is double for the counter-direction of the trajectories.

Replacing

$t = \frac{29000m}{7676m/s}$

$t = 3.778s$

Therefore the time required is 3.778s

4 0

3 years ago

A force of 20.0 N is applied to a 3.00 kg object for 4.00 seconds. Calculate the impulse experienced by the object.

GenaCL600 [577]

Answer:

Impulse = 80Ns

Explanation:

Given the following data;

Mass = 3kg

Force = 20N

Time = 4 seconds

To find the impulse experienced by the object;

Impulse = force * time

Impulse = 20*4

Impulse = 80Ns

Therefore, the impulse experienced by the object is 80 Newton-seconds.

7 0

3 years ago

The terminals of a 0.70 Vwatch battery are connected by a 80.0-m-long gold wire with a diameter of 0.200 mm What is the current

Komok [63]

Answer:

$I=0.047A$

Explanation:

Let's use Ohm's law:

$V=IR$

$I=\frac{V}{R}$ (1)

Where:

$V=Voltage\\I=Current\\R=Electrical\hspace{2 mm}Resistance$

We know the value of the voltage V, so we need to find the value of R in order to find I. Fortunately there is a relation between the resistivity of a conductor and its electrical resistance given by:

$R=\rho*\frac{l}{A}$ (2)

Where:

$R=Electrical\hspace{2 mm}Resistance\\l=Length\hspace{2 mm}of\hspace{2 mm}the\hspace{2 mm}conductor=80m\\A=Cross\hspace{2 mm}sectional\hspace{2 mm}area\hspace{2 mm}of\hspace{2 mm}the\hspace{2 mm}conductor=1.256637061*10^{-7} \\\rho=Electrical\hspace{2 mm}resistivity\hspace{2 mm}of\hspace{2 mm}the\hspace{2 mm}material=2.35*10^{-8}$

Keep in mind that the electrical resistivity of the gold is a known constant which is $\rho_g_o_l_d=2.35*10^{-8}$ and the cross sectional area of the conductor is calculated as: