All categories

3 years ago

0.235 moles of a diatomic gas expands doing 205 J of work while the temperature drops 88 K. Find Q.? (Unit=J)

Physics

1 answer:

Harman [31]3 years ago

5 0

The heat released by the gas is -225 J

Explanation:

First of all, we have to calculate the change in internal energy of the gas, which for a diatomic gas is given by

$\Delta U = \frac{5}{2}nR\Delta T$

where

n = 0.235 mol is the number of moles

$R=8.314\cdot J/mol K$ is the gas constant

$\Delta T = -88 K$ is the change in temperature

Substituting,

$\Delta U = \frac{5}{2}(0.235)(8.314)(-88)=-430 J$

Now we can us the 1st law of thermodynamics to find the heat absorbed/released by the gas:

$\Delta U = Q -W$

where

$\Delta U = -430 J$ is the change in internal energy

Q is the heat

W = 205 J is the heat done by the gas

Solving for Q,

$Q=\Delta U + W = -430 + 205 =-225 J$

Since the sign is negative, it means the heat has been released by the gas.

Learn more about thermodynamics:

brainly.com/question/4759369

brainly.com/question/3063912

brainly.com/question/3564634

#LearnwithBrainly

You might be interested in

1. Apply a constant force of 50 N directed to the right of the 50 kg Box. (2 pts)

kotegsom [21]

As the box is moving with a constant velocity, the two forces acting on the box are canceling each other.

Then friction force = 80 Newtons but in the opposite direction.

Friction force = Mu * Normal force exerted by ground = Mu * weight of box

So we find Mu.

Mu = coefficient of friction between box and horizontal surface

= Force of friction / weight = 80 / 50 * 9.81 = 0.163

When an identical box is placed on top, the force of friction is

= Mu * total weight = 0.163 * (50+50) * 9.81 = 159.9 Newtons

7 0

2 years ago

A sample of argon gas (molar mass 40 g) is at four times the absolute temperature of a sample of hydrogen gas (molar mass 2 g).

qaws [65]

To solve this problem, let us recall that the formula for gases assuming ideal behaviour is given as:

rms = sqrt (3 R T / M)

where

R = gas constant = 8.314 Pa m^3 / mol K

T = temperature

M = molar mass

Now we get the ratios of rms of Argon (1) to hydrogen (2):

rms1 / rms2 = sqrt (3 R T1 / M1) / sqrt (3 R T2 / M2)

rms1 / rms2 = sqrt ((T1 / M1) / (T2 / M2))

rms1 / rms2 = sqrt (T1 M2 / T2 M1)

Since T1 = 4 T2

rms1 / rms2 = sqrt (4 T2 M2 / T2 M1)

rms1 / rms2 = sqrt (4 M2 / M1)

and M2 = 2 while M1 = 40

rms1 / rms2 = sqrt (4 * 2 / 40)

rms1 / rms2 = 0.447

Therefore the ratio of rms is:

rms_Argon / rms_Hydrogen = 0.45

7 0

3 years ago

A sample of gas in a syringe releases heat to its surroundings while the

blsea [12.9K]

Answer: b

Explanation:

When heat is released by the system i.e. system loses heat. So, we take it as negative -Q

When the work is done on the system then it is considered as negative work on the system i.e. -W

In this case, the plunger is pulled out, and work is done on the system. So, we take work as negative work -W

Correct option is b

3 0

2 years ago

Read 2 more answers

In 1965, a group of students wore black arm bands to school in protest of American policies in Vietnam. Administrators banned th

Ede4ka [16]

Answer:

protected under students first amendment rights

Explanation:

did the studyisland :)

4 0

3 years ago

How can we tell when forces are acting on an object (science)

iren [92.7K]

If an object's speed changes, or if it changes the direction it's moving in,
then there must be forces acting on it. There is no other way for any of
these things to happen.

Once in a while, there may be a group of forces (two or more) acting on
an object, and the group of forces may turn out to be "balanced". When
that happens, the object's speed will remain constant, and ... if the speed
is not zero ... it will continue moving in a straight line. In that case, it's not
possible to tell by looking at it whether there are any forces acting on it.

4 0

3 years ago