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3 years ago

0.235 moles of a diatomic gas expands doing 205 J of work while the temperature drops 88 K. Find Q.? (Unit=J)

Physics

1 answer:

Harman [31]3 years ago

5 0

The heat released by the gas is -225 J

Explanation:

First of all, we have to calculate the change in internal energy of the gas, which for a diatomic gas is given by

$\Delta U = \frac{5}{2}nR\Delta T$

where

n = 0.235 mol is the number of moles

$R=8.314\cdot J/mol K$ is the gas constant

$\Delta T = -88 K$ is the change in temperature

Substituting,

$\Delta U = \frac{5}{2}(0.235)(8.314)(-88)=-430 J$

Now we can us the 1st law of thermodynamics to find the heat absorbed/released by the gas:

$\Delta U = Q -W$

where

$\Delta U = -430 J$ is the change in internal energy

Q is the heat

W = 205 J is the heat done by the gas

Solving for Q,

$Q=\Delta U + W = -430 + 205 =-225 J$

Since the sign is negative, it means the heat has been released by the gas.

Learn more about thermodynamics:

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