0.235 moles of a diatomic gas expands doing 205 J of work while the temperature drops 88 K. Find Q.? (Unit=J)
1 answer:
The heat released by the gas is -225 J
Explanation:
First of all, we have to calculate the change in internal energy of the gas, which for a diatomic gas is given by
where
n = 0.235 mol is the number of moles
is the gas constant
is the change in temperature
Substituting,
Now we can us the 1st law of thermodynamics to find the heat absorbed/released by the gas:
where
is the change in internal energy
Q is the heat
W = 205 J is the heat done by the gas
Solving for Q,
Since the sign is negative, it means the heat has been released by the gas.
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Answer:
Average density of Sun is 1.3927 .
Given:
Radius of Sun = 7.001 × km = 7.001 ×
cm
Mass of Sun = 2 × kg = 2 ×
g
To find:
Average density of Sun = ?
Formula used:
Density of Sun =
Solution:
Density of Sun is given by,
Density of Sun =
Volume of Sun =
Volume of Sun =
Volume of Sun = 1.436 ×
Density of Sun =
Density of Sun = 1.3927
Thus, Average density of Sun is 1.3927 .
a) the number of protons is more than the electrons
b)
Explanation:
The net electric charge on the ball is
This electric charge is given by the algebraic sum of the charge of the protons and of the charge of the electrons.
The charge of one proton is:
While the charge of one electron is
So the net charge on the metal ball will be given by
where
is the number of protons
is the number of electrons
So we find:
This means that the number of protons is more than the electrons.
b)
In this case, we want to make the ball neautral, so we have to remove a net charge of Q' such that the new charge is zero:
This implies that the charge that we must remove is
To do that (and to make the ball losing mass at the same time), we have to remove protons, since they have positive charge.
The number of protons that must be removed is:
The mass of one proton is
Therefore, the total mass that must be removed from the ball is