Assume you have measured your little metal sphere's diameter to be 2.500 ± 0.005 cm and its mass to be 63.00 ± 0.05 g.
1 answer:
Answer:
V = (8.2 ± 0.1) cm³
, % = 1.2%
Explanation:
The volume of the sphere is
V = 4/3 π r³
The error in volume is
ΔV = 4 / 3 π r² Δr
DV = 4 π r² Δr
Let's calculate
V = 4/3 π (2.500 / 2)³
V = 8,181 cm³
ΔV = 4 π 2,500²/4 0.005
ΔV = 0.098 cm³
V = (8.2 ± 0.1) cm³
The equation for the percentage error is
% = ΔV / V 100
% = 0.1 / 8.2 100
% = 1.2%
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