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3 years ago

Assume you have measured your little metal sphere's diameter to be 2.500 ± 0.005 cm and its mass to be 63.00 ± 0.05 g.

Physics

1 answer:

TiliK225 [7]3 years ago

5 0

Answer:

V = (8.2 ± 0.1) cm³ , % = 1.2%

Explanation:

The volume of the sphere is

V = 4/3 π r³

The error in volume is

ΔV = 4 / 3 π r² Δr

DV = 4 π r² Δr

Let's calculate

V = 4/3 π (2.500 / 2)³

V = 8,181 cm³

ΔV = 4 π 2,500²/4 0.005

ΔV = 0.098 cm³

V = (8.2 ± 0.1) cm³

The equation for the percentage error is

% = ΔV / V 100

% = 0.1 / 8.2 100

% = 1.2%

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