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Maru [420]
3 years ago
10

He local high school track team practices on an oval running track. One lap of the track is 1/4 of a mile. - Write an expression

that represents the total distance run based on the number of laps, p, completed. - Determine the total distance run, if a member of the track team completes 22 laps. - Provide work and/or an explanation at how you arrived at your answer.
Mathematics
1 answer:
NNADVOKAT [17]3 years ago
6 0

Answer:

Step-by-step explanation:

On the oval track, one lap is 1/4 of a mile. If p laps are completed, the expression that represents the total distance run based on the number of laps is

p × 1/4 = p/4 miles

With the above expression, we would determine the number of miles run buy a team member if we are given the number of laps by just inputting the number of laps for p. Therefore,

if a member of the track team completes 22 laps, the total distance covered by the member would be

22 × 1/4 = 5.5 miles

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jeka94

Answer:

  see below

Step-by-step explanation:

The mapping tells you how to find the vertices of the image:

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blsea [12.9K]

Answer:

3/2

Step-by-step explanation:

sin(3π/4 - β) = sin(3π/4)cosβ - cos(3π/4)sinπ =

\sin(\frac{3\pi}{4}-\beta)=\sin(\frac{3\pi}{4})\cos\beta-\cos\frac{3\pi}{4}\sin\beta\\=\frac{1}{\sqrt{2}}\cos\beta-(-\frac{1}{\sqrt{2}})\sin\beta\\\\=\frac{1}{\sqrt{2}}(\cos\beta +\sin\beta)\\\\\sin^2(\frac{3\pi}{4}-\beta)=\frac{1}{2}\cos\beta +\sin\beta)^2=\frac{1}{2}(\cos^2\beta +\sin^2\beta+2\sin\beta\cos\beta\\=\frac{1}{2}(1+\sin2\beta)=\frac{1}{2}(1-\frac{1}{5}) = \frac{2}{5}\\

Use \cot^2x=\csc^2x-1=\frac{1}{\sin^2x}-1

so

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