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Maru [420]
3 years ago
10

He local high school track team practices on an oval running track. One lap of the track is 1/4 of a mile. - Write an expression

that represents the total distance run based on the number of laps, p, completed. - Determine the total distance run, if a member of the track team completes 22 laps. - Provide work and/or an explanation at how you arrived at your answer.
Mathematics
1 answer:
NNADVOKAT [17]3 years ago
6 0

Answer:

Step-by-step explanation:

On the oval track, one lap is 1/4 of a mile. If p laps are completed, the expression that represents the total distance run based on the number of laps is

p × 1/4 = p/4 miles

With the above expression, we would determine the number of miles run buy a team member if we are given the number of laps by just inputting the number of laps for p. Therefore,

if a member of the track team completes 22 laps, the total distance covered by the member would be

22 × 1/4 = 5.5 miles

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What is the inverse of the function f(x) = x – 12?
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Answer:

f(x)^-1=x+12

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Hope it helps.

6 0
3 years ago
Read 2 more answers
Point C is on line segment \overline{BD} BD . Given CD=x,CD=x, BC=5x-5,BC=5x−5, and BD=2x+7,BD=2x+7, determine the numerical len
NARA [144]

Answer:

CD = 3

Step-by-step explanation:

Given

CD = x

BC = 5x - 5

BD = 2x + 7

Required

Determine CD

Since, C is a point on BD, the relationship between the given parameters is;

BD = BC + CD

Substitute the values of BD, BC and CD

2x + 7 = 5x - 5 + x

Collect Like Terms

2x - 5x - x = -5 - 7

-4x = -12

Divide both sides by -4

\frac{-4x}{-4} = \frac{-12}{-4}

x = 3

To determine the length of CD;

Substitute 3 for x in CD = x

Hence;

CD = 3

3 0
3 years ago
the volume of a cube is increasing at a constant rate of 824 cubic centimeters per minute. At the instant when the volume of the
Maurinko [17]

Answer:

DA/dt  = 75.27 cm²

Step-by-step explanation:

Cube Volume    =   V(c)   =  683  cm³

DV(c) /dt    =  824 cm³

V(c,x) = x³    

Then

DV(c,x)/ dt   =  3x² Dx/dt

( DV(c,x)/ dt )/ 3x²  =  Dx/dt       (1)

Now  as  V(c,x) = x³    when    V(c,x)  =  683 cm³     x = ∛683

x  =  8.806     ( from excel)

And by subtitution of this value in equation (1)

Dx/dt   =  ( DV(c,x)/ dt )/ 3x²   ⇒  Dx/dt  =  824 / 3*x²

  Dx/dt   = 824 /3*77.55

Dx/dt   =  824/232,64

Dx/dt   = 3,542

Then we got  Dx/dt  where x is cube edge. The area of the face is x² then

the rate of change of the suface area is  

DA/dt  = ( Dx/dt )²*6         ( 6 faces of a cube)

DA/dt  = (3.542)²*6

DA/dt  = 75.27 cm²

6 0
2 years ago
Tanya paid $75 to join a summer gold program. The course where she plays charges $30 per round. Since she is a student, she rece
Crazy boy [7]
Tanya played 15 rounds.
375-75=300
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