Answer:
The probability that exactly 19 of them are strikes is 0.1504
Step-by-step explanation:
The binomial probability parameters given are;
The probability that the pitcher throwing a strike, p = 0.675
The probability that the pitcher throwing a ball. q = 0.325
The binomial probability is given as follows;

Where:
x = Required probability
Therefore, the probability that the pitcher throws 19 strikes out of 29 pitches is found as follows;
The probability that exactly 19 of them are strikes is given as follows;
Hence the probability that exactly 19 of them are strikes = 0.1504
3(2x+8)=8x+46
6x+24=8x+46
-2x+24=46
-2x=22
x=-11
3(2(-11)+8)=8(-11)+46
3(-22+8)=-88+46
3(-14)=-42
-42=-42
Hope I didn't mess up for your sake
So... let's say the amounts invested were "a" at 6% and "b" at 7.5%.
ok.. hmm what's 6% of a? well, (6/100) * a or 0.06a.
what's 7.5% of b? well, (7.5/100) * b or 0.075b.
now... we know, whatever "a" and "b" are, they total the investment of 5000 bucks, thus
a + b = 5000and the interest yielded was 337.50, thus
0.06a + 0.075b = 337.50thus

solve for "a", to see how much was invested at 6%.
what about "b"? well, b = 5000 - a.