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Umnica [9.8K]
3 years ago
15

Only smart bros answer

Mathematics
1 answer:
Naddik [55]3 years ago
6 0

Answer:

178.695

Step-by-step explanation:

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Maureen spent sh 207to buy 7 exercise books and 4 pens while Sharon spent sh 165 to buy 5 exercise books and 5 pens of same type
Gnesinka [82]

Answer:

The cost of each exercise book is 25 sh.

The cost of each pen is 8 sh.

Step-by-step explanation:

Write down the system of equations and then solve.

\begin{bmatrix}7b+4p=207\\ 5b+5p=165\end{bmatrix}\\\\\mathrm{The\:solutions\:to\:the\:system\:of\:equations\:are:}\\\\b=25,\:p=8

Best Regards!

8 0
3 years ago
Read 2 more answers
A cylinder has a radius of 8 cm and a height of 14 cm.
Wewaii [24]
Radius, r = 8 cm
Height, h = 14 cm

Volume = πr²h

= π × (8)² × 14
= 896π cm³
7 0
4 years ago
Which expression is equivalent to sin(2x) cosx
Vsevolod [243]

Answer:

2sin(x)cos^2(x)

Step-by-step explanation:

To solve the problem, you must expand the trigonometric expression using the information given.

sin(2x)cosx\\sin(2x)\\=2sin(x)\\=2sin(x)cos^2(x)

7 0
2 years ago
Consider the curve defined by the equation y=6x2+14x. Set up an integral that represents the length of curve from the point (−2,
torisob [31]

Answer:

32.66 units

Step-by-step explanation:

We are given that

y=6x^2+14x

Point A=(-2,-4) and point B=(1,20)

Differentiate w.r. t x

\frac{dy}{dx}=12x+14

We know that length of curve

s=\int_{a}^{b}\sqrt{1+(\frac{dy}{dx})^2}dx

We have a=-2 and b=1

Using the formula

Length of curve=s=\int_{-2}^{1}\sqrt{1+(12x+14)^2}dx

Using substitution method

Substitute t=12x+14

Differentiate w.r t. x

dt=12dx

dx=\frac{1}{12}dt

Length of curve=s=\frac{1}{12}\int_{-2}^{1}\sqrt{1+t^2}dt

We know that

\sqrt{x^2+a^2}dx=\frac{x\sqrt {x^2+a^2}}{2}+\frac{1}{2}\ln(x+\sqrt {x^2+a^2})+C

By using the formula

Length of curve=s=\frac{1}{12}[\frac{t}{2}\sqrt{1+t^2}+\frac{1}{2}ln(t+\sqrt{1+t^2})]^{1}_{-2}

Length of curve=s=\frac{1}{12}[\frac{12x+14}{2}\sqrt{1+(12x+14)^2}+\frac{1}{2}ln(12x+14+\sqrt{1+(12x+14)^2})]^{1}_{-2}

Length of curve=s=\frac{1}{12}(\frac{(12+14)\sqrt{1+(26)^2}}{2}+\frac{1}{2}ln(26+\sqrt{1+(26)^2})-\frac{12(-2)+14}{2}\sqrt{1+(-10)^2}-\frac{1}{2}ln(-10+\sqrt{1+(-10)^2})

Length of curve=s=\frac{1}{12}(13\sqrt{677}+\frac{1}{2}ln(26+\sqrt{677})+5\sqrt{101}-\frac{1}{2}ln(-10+\sqrt{101})

Length of curve=s=32.66

5 0
3 years ago
Need a GED Math test tutor. Comment if I can give you my number to help​
love history [14]

Answer:

sure I'll help, 59.99 per hour. it's a pretty solid deal.

Step-by-step explanation:

3 0
3 years ago
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