The force required for the car is 5841 N
Explanation:
First of all, we need to find the acceleration of the car, which is given by:
where:
v = 27 m/s is the final velocity of the car
u = 0 is the initial velocity (the car starts from rest)
t = 6 s is the time the car takes to accelerate from u to v
Substituting, we find
Now we can find the force needed to accelerate the car; using Newton's second law of motion,
where:
F is the net force on the car
m = 1298 kg is the mass of the car
is the acceleration
Substituting, we find:
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Answer:
V= 14.2m/s
Explanation:
We know that acceleration= dv/dt
So 16m/s²=dv/ dt = v dv/ds
So this wil be
Integral of 16m/s² ds [at 2,2]= integral of v dv at[ 0, v]
So 16[s (3/2)/3/2] at ( s,3) = v²/2
At s= 6m
So v² = 64/3( 6^1.5-3^1.5)
= 14.2m/s
Answer:
20.6 cm
Explanation:
charge per cm = 0.14 μC
number of electrons (e) =
to get the length of tape pulled we can apply the formula below
length of tape =
therefore we need to find the magnitude of the charge of the electrons
- 1 electron = C
now that we have the magnitude of the charge, we can find the length of the tape
- length of the tape = = 20.6 cm