Answer:
The resultant velocity of the jet as a vector in component form 426.87 mi/hr 5.36 degrees North.
Explanation:
Vectors are quantities that have their magnitude and direction .
Sketching out the problem given, by using straight lines to represent each of the vectors, we will have a right angled triangle as shown below.
The solution can be obtained by applying Pythagoras theorem to
resolve the vectors.
Velocity of jet plane = 425 mi/hr
velocity of air = 40 mi/hr
Resultant of the vectors =![\sqrt[]{425^{2}+40^{2}}=426.87](https://tex.z-dn.net/?f=%5Csqrt%5B%5D%7B425%5E%7B2%7D%2B40%5E%7B2%7D%7D%3D426.87)
mi/hr
Vector direction =
hence the velocity is 426.87 mi/hr in a direction 5.36 degrees inclined Northward
Answer:
Explanation:
Here we know that initial temperature of ice is given as
now the latent heat of ice is given as
now we also know that the mass of ice is
so here we know that heat required to change the phase of the ice is given as
Answer:
B. IT should have a very broad focus with many variables.
Answer:
a
The orbital speed is 
b
The escape velocity of the rocket is 
Explanation:
Generally angular velocity is mathematically represented as
Where T is the period which is given as 1.6 days = 
Substituting the value
At the point when the rocket is on a circular orbit
The gravitational force = centripetal force and this can be mathematically represented as
Where G is the universal gravitational constant with a value 
M is the mass of the earth with a constant value of 
r is the distance between earth and circular orbit where the rocke is found
Making r the subject
![r = \sqrt[3]{\frac{GM}{w^2} }](https://tex.z-dn.net/?f=r%20%3D%20%5Csqrt%5B3%5D%7B%5Cfrac%7BGM%7D%7Bw%5E2%7D%20%7D)
![= \sqrt[3]{\frac{6.67*10^{-11} * 5.98*10^{24}}{(4.45*10^{-5})^2} }](https://tex.z-dn.net/?f=%3D%20%5Csqrt%5B3%5D%7B%5Cfrac%7B6.67%2A10%5E%7B-11%7D%20%2A%205.98%2A10%5E%7B24%7D%7D%7B%284.45%2A10%5E%7B-5%7D%29%5E2%7D%20%7D)
The orbital speed is represented mathematically as
Substituting value
The escape velocity is mathematically represented as
Substituting values
Answer:
0.229 seconds
Explanation:
Given:
y₀ = 80.6 m
v₀ = 0 m/s
a = -9.8 m/s²
We need to find the difference in times when y = 10.8 m and y = 2.10 m.
When y = 10.8 m:
y = y₀ + v₀ t + ½ at²
10.8 = 80.6 + (0) t + ½ (-9.8) t²
10.8 = 80.6 − 4.9 t²
4.9 t² = 69.8
t = 3.774
When y = 2.10 m:
y = y₀ + v₀ t + ½ at²
2.10 = 80.6 + (0) t + ½ (-9.8) t²
2.10 = 80.6 − 4.9 t²
4.9 t² = 78.5
t = 4.003
The difference is:
4.003 − 3.774 = 0.229
The man has 0.229 seconds to get out of the way.
