1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Zanzabum
4 years ago
11

Tidal forces are gravitational forces exerted on different parts of a object by a second object. Their effects are particularly

visible on Earth's surface in the form of tides. To understand the origin of tidal forces, consider Earth-Moon system to consist of two spherical bodies, each with a spherical mass distribution. Let RE be the radius of Earth, m be the mass of the Moon, and G be the gravitational constant.
1) Earth is subject not only to the gravitational force of the Moon but also to the gravitational pull of the Sun. However, Earth is much farther away from the Sun than it is from the Moon. In fact, the center of Earth is at an average distance of 1.5×1011m from the center of the Sun. Given that the mass of the Sun is 1.99×1030kg, which of the following statements is correct?

A) The force exerted on Earth by the Sun is weaker than the corresponding force exerted by the Moon.
B) The force exerted on Earth by the Sun is stronger than the corresponding force exerted by the Moon.
C) The force exerted on Earth by the Sun is of the same order of magnitude of the corresponding force exerted by the Moon.

2) The occurrence of tidal forces on Earth's surface is not limited to the gravitational effects of the Moon. Tidal forces are produced every time different parts of a object are subject to different gravitational forces exerted by a second object. Therefore, tidal forces due to the gravitational effects of the Sun are also present on Earth's surface. What can you conclude about the relative effects of these two tidal forces on Earth's surface?

A) The Moon exerts a stronger tidal force on Earth than the Sun does.
B) The Sun exerts a stronger tidal force on Earth than the Moon does.
C) The Moon and the Sun cause tidal forces of equal magnitude.
Physics
1 answer:
Elden [556K]4 years ago
8 0

Answer:

1.

B) The force exerted on Earth by the Sun is stronger than the corresponding force exerted by the Moon.

Explanation:

Gravitational force is proportional to the products of the masses of the bodies and inversely proportional to the square of their distance apart.

2.

A) The Moon exerts a stronger tidal force on Earth than the Sun does

Explanation:

the Moon produces a greater tidal force on the Earth than the Sun, even though the Sun exerts a greater gravitational attraction on the earth than that exerted b the moon on the earth.

The Sun's gravitational pull on the Earth is about 175 times stronger when compared to that exerted by the Moon but has a much smaller effect on the tides. This is due to the inverse square law. The Earth's diameter is a tiny fraction of the total distance between the Sun and Earth which means that the difference in gravitational force across the Earth varies by a very small amount. On the other hand, the Moon is much closer than the Sun, thus the difference in gravitational force from the Moon across the Earth is much greater. The Sun has approximately only 44% of tidal influence than that of the Moon.

You might be interested in
The same ball is shot straight up a second time from the same gun, but this time the spring is compressed only half as far befor
Mekhanik [1.2K]

Answer:

The new height the ball will reach = (1/4) of the initial height it reached.

Explanation:

The energy stored in any spring material is given as (1/2)kx²

This energy is converted to potential energy, mgH, of the ball at its maximum height.

If the initial height reached is H

And the initial compression of the spring = x

So, mgH = (1/2)kx²

H = kx²/2mg

The new compression, x₁ = x/2

New energy of loaded spring = (1/2)kx₁²

And the new potential energy = mgH₁

mgH₁ = (1/2)kx₁²

But x₁ = x/2

mgH₁ = (1/2)k(x/2)² = kx²/8

H₁ = kx²/8mg = H/4 (provided all the other parameters stay constant)

6 0
4 years ago
If the pendulum took longer to complete one oscillation, how would the graph change?
pickupchik [31]

We don't know what kind of graph it is.

For example, it might be a graph of the pendulum's distance from center,

angle from center, speed, acceleration, total distance swung since it was

started, mass, weight, temperature, etc.


If the graph shows the pendulum's distance from center, angle from center,

speed, or acceleration, then the graph will look like a wave, with the period

of the wave being the period of the pendulum's oscillation. If the pendulum

took longer to complete one oscillation, that means its PERIOD increased,

and the distance between the peaks of the graph would be longer.


If it was a graph of total distance the pendulum swung since it was started,

the graph wouldn't look like a wave, just a steadily rising wiggle line. If the

pendulum took longer to complete one oscillation, the wiggles in the line

would be farther apart, and the average slope of any large section of the

line would be less.


If it was a graph of the pendulum's mass, weight, temperature, cost, etc.,

then the graph would be a horizontal line, and nothing that might change

the period of oscillation would have any effect on the graph.

7 0
3 years ago
Read 2 more answers
What is a gravitational wave and why was it so hard to detect?
Alika [10]

Answer:

gravitational waves are ripples in spece-time caused primarily when objects are accelerated and the energy for the acceleration is transpoted as gravitational radiation.

they are difficult to detect because they require very sensitive technology or you will have to wait unitl black holes collide.

5 0
3 years ago
What is the magnitude (size) and direction of the cumulative force acting on the car shown in the picture above?
mrs_skeptik [129]

Answer:

5070

Explanation:

add them up and then you get <em>your</em><em> </em><em>answers</em><em> </em>

5 0
3 years ago
Read 2 more answers
If a 5 N force pushes a 20 kg mass on a frictionless surface, how fast is the mass going in 5 seconds.
stira [4]

Explanation:

Let me know if you have questions

3 0
4 years ago
Other questions:
  • Find the cube roots of 27(cos 327° + i sin 327° ). Write the answer in trigonometric form.
    15·1 answer
  • Part 1: What are the two groups of planets based on composition?
    9·1 answer
  • An object has a positive velocity to the right and a negative acceleration. what is the motion of the object?
    11·1 answer
  • A box is being pushed but two stellar science students, one on each side of the box. Peter is pushing box with a force of 10 N t
    15·1 answer
  • How much power is needed to push a 95 kg chest at 0.67 m/s along a horizontal floor where the coefficient of friction is 0.77?
    10·1 answer
  • Two objects of equal mass are a fixed distance apart. If the mass of each object could be tripled, the gravitational force betwe
    7·1 answer
  • While waiting for his Mom to come out of the hairdresser's, Sean accidentally puts the car in gear and it begins to roll forward
    6·1 answer
  • 2. How does inherent value differ from instrumental value? *
    12·1 answer
  • Question 10 of 15<br> If the period of a wave increases, its frequency must blank
    13·1 answer
  • Physics 4
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!