Question

We have seen in lab that when adhesive tape is pulled from a dispenser, the detached tape has a positive charge. If the tape pulled from the dispenser was electrically neutral before it was pulled, and if it has 0.14 microcoulombs of charge per centimeter after being pulled, approximately what length of tape must be pulled if a total of 1.8 10^13 electrons are transferred during the pulling ?

Answer 1

Answer:

20.6 cm

Explanation:

charge per cm = 0.14 μC

number of electrons (e) =  $1.8 x 10^{13}$

to get the length of tape pulled we can apply the formula below

length of tape = $\frac{magnitude of charge of the electrons}{charge per cm}$

therefore we need to find the magnitude of the charge of the electrons

• 1 electron = $1.602 x 10^{-19}$ C

         $1.8 x 10^{13} electrons = 1.8 x 10^{13} x 1.602 x 10^{-19} = 2.88μC}$

now that we have the magnitude of the charge, we can find the length of the tape

• length of the tape =  $\frac{2.88}{0.14}$ = 20.6 cm