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4 years ago

HELP!! Worth a lot of points :) (Physics question)

Physics

2 answers:

Temka [501]4 years ago

8 0

My answer would be B.
Source:
i had this question before.
Hope that this helps you! =)

nadezda [96]4 years ago

6 0

It's B if that helps at all :) (I'm like, 98% sure that it's totally B!

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Atoms are happy (they will not readily react with other elements) when they have a full outside ring of

Len [333]

Answer: TRUE

Explanation:

Atoms are happy when they will not react with other elements while having a full outside ring of electrons because this makes them to be noble.

A stable atom possesses full outside ring of electrons while unstable one does not. So, they are happy also because of stability.

7 0

3 years ago

A 49 kg bear slides, from rest, 11 m down a lodgepole pine tree, moving with a speed of 3.3 m/s just before hitting the ground.

hichkok12 [17]

Answer:

a) $\Delta U_g=-5.3kJ$

b) $K=0.27kJ$

c) $F_f=0.45kN$

Explanation:

the gravitational potential energy is given by:

$U_g=m.g.h\\$

$\Delta U_g=m.g.h_f-m.g.h_i\\\Delta U_g=49kg*9.8m/s^2*(0m-11m)\\\Delta U_g=-5.3kJ$

The kinetic energy is given by:

$K=\frac{1}{2}m.v^2\\$

the initial kinetic energy is zero because the motion started from rest, so:

$K=\frac{1}{2}*49kg*(3.3m/s^2)^2\\K=0.27kJ$

applying the conservation of energy theorem:

$U_g-W_f=K_f\\W_f=-(\Delta K+\Delta U)\\W_F=5.3kJ-0.27kJ\\W_F=-5.0kJ$

The work done by the friction force is given by:

$W_f=F_f.h.cos(\theta)\\$

the angle of the force is 180 degrees because it's against the movement:

$F_f=\frac{W_f}{h.cos(\theta)}\\\\F_f=\frac{-5.0kJ}{11m.cos(180^o)}\\\\F_f=0.45kN$

8 0

4 years ago

Which of the following is an important step in the process of conflict resolution?

4vir4ik [10]

A would be the correct answer. Its the only one to make sense since you are trying to solve the conflict!

7 0

4 years ago

Read 2 more answers

A 15 kg object and a 18 kg object are connected by a massless compressed spring and

MatroZZZ [7]

Hi there!

This is an example of a recoil collision.

Using the conservation of momentum:

$p_i = p_f$

The initial momentum is 0 kgm/s (objects start from rest), so:

$p_f = 0$

We are given that the 15 kg block has a velocity of 12 m/s to the left, so:

$m_1v_1' + m_2v_2' = 0 \\\\15(-12) + 18v_2' = 0 \\\\$

Solve for v2':

$18v_2' = 180 \\\\v_2' = \boxed{10 m/s}$

5 0

3 years ago

Five men push a stalled car with an average force of 400 N per person. Find the mass of the

timama [110]

The mass of the car is 2000 kg

Explanation:

We can solve this problem by using Newton's second law of motion, which states that the net force acting on an object is equal to the product between the mass of the object and its acceleration:

$\sum F = ma$

where

$\sum F$ is the net force

m is the mass

a is the acceleration

In this problem, we have:

$a=1 m/s^2$ is the acceleration of the car

Each person applies a force of 400 N, and there are five men, so the total force applied is

$\sum F = 5\cdot 400 N = 2000 N$

Therefore, the mass of the car is:

$m=\frac{\sum F}{a}=\frac{2000 N}{1 m/s^2}=2000 kg$

Learn more about Newton's second law of motion:

brainly.com/question/3820012

#LearnwithBrainly

4 0

4 years ago