Answer:
Option A is the correct answer.
Explanation:
The given pyramid has 3 lateral triangular side as shown below.
Base of triangle = 12 unit
We need to find perpendicular.
By Pythagoras theorem we have
Perpendicular² = 10²-6²
Perpendicular = 8 unit
So area of 1 lateral triangle = 1/2 x Base x Perpendicular.
= 1/2 x 12 x 8 = 48 unit²
Area of lateral side = 3 x 48 = 144 unit²
Option A is the correct answer.
Answer:
In a quadratic equation of the shape:
y = a*x^2 + b*x + c
we hate that the discriminant is equal to:
D = b^2 - 4*a*c
This thing appears in the Bhaskara's formula for the roots of the quadratic equation:
You can see that the determinant is inside a square root, this means that if D is smaller than zero we will have imaginary roots (the graph never touches the x-axis)
If D = 0, the square root term dissapear, and this implies that both roots of the equation are the same, this means that the graph touches the x axis in only one point, wich coincides with the minimum/maximum of the graph)
If D > 0 we have two different roots, so the graph touches the x-axis in two different points.
