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KatRina [158]
3 years ago
10

Hii please help i’ll give brainliest if you give a correct answer please please hurry

Physics
2 answers:
podryga [215]3 years ago
6 0
The first one is the correct one
Andru [333]3 years ago
6 0
The answer is A.
Because
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4. A vehicle
Gnom [1K]

Answer:

Average acceleration, a=2.77\ m/s^2

Explanation:

Given that,

Initial velocity, u = 0 km/h

Final velocity, v = 100 km/h = 27.77 m/s

Time, t = 10 s

We need to find the average acceleration of the vehicle. It is given by the change in velocity divided by time. Som,

a=\dfrac{v-u}{t}\\\\a=\dfrac{27.77-0}{10}\\\\a=2.77\ m/s^2

So, its average acceleration is 2.77\ m/s^2.

5 0
4 years ago
Which sources of associated with the line emission spectrum?
Lerok [7]

Answer:

Answer if this question neon street sign

Explanation:

may this answer is helpful for you

3 0
3 years ago
A historical society is testing an old cannon. They
sveta [45]

Answer:

26.2 m/s

Explanation:

We can find the speed of the cannonball just by analyzing its vertical motion. In fact, the initial vertical velocity is

u_y = u sin \theta (1)

where u is the initial speed and \theta = 45.0^{\circ} is the angle of projection.

We can therefore use the following suvat equation for the vertical motion of the ball:

v_y = u_y + at

where v_y is the vertical velocity at time t, and a=g=-9.8 m/s^2 is the acceleration of gravity. The time of flight is 3.78 s, so we know that the ball reaches its maximum height at half this time:

t=\frac{3.78}{2}=1.89 s

And at the maximum height, the vertical velocity is zero:

v_y=0

Substituting these values, we find the initial vertical velocity:

u_y = v_y - at = 0-(-9.8)(1.89)=18.5 m/s

And using eq.(1) we now find the initial speed:

u=\frac{u_y}{sin \theta}=\frac{18.5}{sin 45.0^{\circ}}=26.2 m/s

4 0
3 years ago
A consistent tendency for forecasts to be greater or less than the actual values is called​ ________ error.
stepladder [879]
The Answer is: Bias Error
8 0
3 years ago
A baseball player hit 60 home runs in a season. Of the 60 home runs, 19 went to right field, 18 went to right center field, 12 w
vlada-n [284]

Answer:

(a) 1/60

(b) Yes, it was unusual.

Explanation:

Number that went to the right field = 19

Number that went to the right center field = 18

Number that went to the center field = 12

Number that went to the left center field = 10

Number that went to the left field = 1

Total number of home runs = 60

(a) The probability that a randomly selected home run was hit to left ​field is

P(left field) = 1/60

(b) It was unusual because whenever a player hit a home run, it most times went to the right field,which is why the right field had the highest probability, 19/60.

On the other hand, it went to the left field the least number of times, which is why the left field had the least probability, 1/60.

So, it was unusual.

5 0
3 years ago
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