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IRINA_888 [86]
3 years ago
5

Consider the function given below.

Mathematics
1 answer:
MAVERICK [17]3 years ago
3 0
You have to put a picture of the problem
You might be interested in
Pls help me with the inverse operation of this problem. Best answer gets brainliest
timurjin [86]

Answer:

x=7

Step-by-step explanation:

I believe we are solving for x. In that case, let us start by moving 1 to the other side.

\frac{4(x+3)}{5} = 8

Now, we want to get rid of that denominator of 5. Let us multiply both sides by 5:

4(x+3)=40

Now, we may divide both sides by 4 to get rid of the coefficiant:

x+3=10

When we subtract both sides by 3, we get

x=7

<em>I hope this helps! :)</em>

6 0
2 years ago
27.) A customer went to a garden shop and bought some potting soil for $17.50 and 4 shrubs. The total bill was $53.50. Write and
Talja [164]

Answer:

c) The equation to find the price of each shrub is    $53.50 = 4 p + $17.50

The cost of 1 shrub = p =  $ 9.00

Step-by-step explanation:

The total number of shrubs purchased = 4

The price paid for potting soil = $17.50

The total bill of purchase = $53.50

Let us assume the cost of 1 shrub   = $p

The total amount spent of 4 shrubs = 4 x ( The price of each shrub)  =  4 p

TOTAL BILL = The amount paid for 4 shrubs +  AMOUNT paid for SOIL

⇒ $53.50 = 4 p + $17.50

Now. solving for p, we get:

53.50 - 17.50  = 4  p

or, 3 6  = 4 p

or, p = 36/4 = 9

or, p = 9

Hence, the cost of each shrub = $9

3 0
3 years ago
Martinbly.com
Lesechka [4]

Answer:

55.5

Step-by-step explanation:

6 0
3 years ago
Can you give me answer to both questions am confused . Thank you .
Naddik [55]
For the first one, it would be 5/3 and 19/3
the second one would be 40
5 0
3 years ago
<img src="https://tex.z-dn.net/?f=y%20%3D%20%20%5Cfrac%7B1%7D%7B2%7D%20%20%2B%20%20%5Cfrac%7Bw%7D%7B3%7D%20" id="TexFormula1" ti
ElenaW [278]

Answer:  \bold{w=\dfrac{6y-3}{2}}

<u>Step-by-step explanation:</u>

Isolate w by performing the following steps

  • Multiply by 6 on both sides to clear the denominator
  • Subtract 3 from both sides
  • Divide both sides by 2

y=\dfrac{1}{2}+\dfrac{w}{3}\\\\\\6\bigg[y=\dfrac{1}{2}+\dfrac{w}{3}\bigg]\quad \implies \quad 6y=3+2w\\\\\\6y-3=3-3+2w\quad \implies \quad 6y-3=2w\\\\\\\dfrac{6y-3}{2}=\dfrac{2w}{2}\quad \implies \quad \large\boxed{\dfrac{6y-3}{2}=w}

5 0
3 years ago
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