Answer:
(a) 0.8 s
(b) t = 7.2 s
Explanation:
(a) Half life expression for second order kinetic is:
![t_{1/2}=\frac{1}{k[A_o]}](https://tex.z-dn.net/?f=t_%7B1%2F2%7D%3D%5Cfrac%7B1%7D%7Bk%5BA_o%5D%7D)
Where,
![[A_o]](https://tex.z-dn.net/?f=%5BA_o%5D)
is the initial concentration = 1.0 M
k is the rate constant = 1.25 M⁻¹s⁻¹
So,
Half life = 0.8 s
(b) Integrated rate law for second order kinetic is:
![\frac{1}{[A_t]} = \frac{1}{[A]_0}+kt](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B%5BA_t%5D%7D%20%3D%20%5Cfrac%7B1%7D%7B%5BA%5D_0%7D%2Bkt)
Where, ![[A_t]](https://tex.z-dn.net/?f=%5BA_t%5D)
is the final initial concentration
For 90% completion, 10% is left. so,
![[A_t]=\frac {10}{100}\times 1.0=0.1\ M](https://tex.z-dn.net/?f=%5BA_t%5D%3D%5Cfrac%20%7B10%7D%7B100%7D%5Ctimes%201.0%3D0.1%5C%20M)
So,
t = 7.2 s
The moles of Al that are needed to react completely with 17 .5 moles of FeO is 11.67 moles
<u><em>calculation</em></u>
2Al +3 FeO → 3 Fe + Al₂O₃
The moles of Al is calculate using the mole ratio
That is; From equation above the mole ratio of Al :FeO is 2:3 therefore the moles of Al
= 17.5 moles x 2/3 = 11.67 moles
Helium give me a thanks or brainiest answer if this helps!
Answer:
// Program is written in C++ Programming Language
// Comments are used for explanatory purpose
// Program Starts here
#include<iostream>
using namespace std;
int main ()
{
// Declare Variables
int quarter, dimes, nickel, cent;
// Enter values for each
cout<<"Quarter: ";
cin>>quarter;
cout<<"Dimes: ";
cin>>dimes;
cout<<"Nickels: ";
cin>>nickel;
/*
In the United States, these coins have the following values
Quarter = 25 cents
Done = 10 cents
Nickel = 5 cent
Total cent is calculated below
*/
cent = 25 * quarter + 10 * dimes + 5 * nickel;
// Print Total
cout<<"The coins are worth "<<cent<<" cents";
return 0;
}
First shell hold 2. second shell can hold up to 8. so it should be 8.
