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3 years ago

13

One of the most common household toxins, benzene can be found in the following:

2 answers:

maksim [4K]3 years ago

7 0

Answer : Option D) Paint Supplies.

Explanation : The paint is usually the major common household toxins, which contains benzene in it. Benzene being carcinogenic in nature is very harmful to humans.

vekshin13 years ago

6 0

Benzene is used as dry cleaning agent so must be found in dry cleaned clothing

It is also used as paint thinner so can be found in pain supplies as well

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A child has a toy balloon with a volume of 1.80 L. The temperature of the balloon when it was filled was 293 K at a pressure of

Mekhanik [1.2K]

Answer:

2.42L

Explanation:

Given parameters:

V₁ = 1.8L

T₁ = 293K

P₁ = 101.3kPa

P₂ = 67.6kPa

T₂ = 263K

Unknown:

V₂ = ?

Solution:

To solve this problem, we are going to use the combined gas law to find the final volume of the gas. The combined gas law expression combines the equation of Boyle's law, Charles's law and Avogadro's law;

$\frac{P_{1} V_{1} }{T_{1} } = \frac{P_{2} V_{2} }{T_{2} }$

All the units are in the appropriate form. We just substitute and solve for the unknown;

101.3 x 1.8 / 293 = 67.6 x V₂ / 263

V₂ = 2.42L

7 0

3 years ago

Give two examples of solutions that you might find or prepare in a kitchen.

amm1812

Explanation:

solid liquid

solid gas

liquid solid

8 0

2 years ago

The change in enthalpy that occurs in the process of converting reactants to products in a chemical reaction is called the _____

zheka24 [161]

Answer:

∆H or Enthalpy of the reaction

Explanation:

If ∆H is +ve

Reaction is exothermic
Example:-Combustion, mixing sodium/potassium in water

If ∆H is -ve

Reaction is endothermic
Ex:-Melting of ice

6 0

2 years ago

Read 2 more answers

What are some things that could happen to you if you have an electrolyte imbalance?

Anestetic [448]

Answer:

fast heart rate, lethargy, fatigue

4 0

3 years ago

Read 2 more answers

What volume of 0.235 M H2SO4 is needed to titrate 40.0 mL of 0.0500 M Na2CO M NaCO3 solution?

Andreyy89

Answer: The volume of 0.235 M $H_2SO_4$ needed to titrate 40.0 mL of 0.0500 M $Na_2CO_3$ is 8.51 ml

Explanation:

To calculate the volume of acid, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is $H_2SO_4$

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is $Na_2CO_3$

We are given:

$n_1=2\\M_1=0.235M\\V_1=?mL\\n_2=2\\M_2=0.0500M\\V_2=40.0mL$

Putting values in above equation, we get:

$2\times 0.235\times V_1=2\times 0.0500\times 40.0\\\\V_1=8.51mL$

Thus volume of 0.235 M $H_2SO_4$ needed to titrate 40.0 mL of 0.0500 M $Na_2CO_3$ is 8.51 ml

5 0

3 years ago