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aev [14]
2 years ago
12

BRAINLIEST PLLLLLLLZZZZZZZ

Mathematics
1 answer:
baherus [9]2 years ago
8 0
The answer would be 3
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What is the perimeter of a rectangle whose width is (x - 7) units and whose length is (3x + 10) units?​
FromTheMoon [43]

Answer:

The answer is "(8x + 6) units".

Step-by-step explanation:

Formula of perimeter is:

\to \bold{P=2 \text{(Length +width)} }

       =2((3x+10)+(x-7))\\\\=2(4x+3)\\\\= 8x+6

4 0
3 years ago
Please help, thanks I’m advance!
netineya [11]

Answer:

A

Step-by-step explanation:

(x+2)©= x©+4x+4

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3 0
3 years ago
Analyze the diagram below and complete the instructions that
Novosadov [1.4K]

9514 1404 393

Answer:

  D.  x = 15; y = 5√3

Step-by-step explanation:

You don't need to know any trig to select the correct answer. You only need to know that the lengths of both sides must be less than the length of the hypotenuse. It is also helpful to know that √3 is about 1.732, so 10√3 ≈ 17.32.

Since x < 10√3, only answer choices A and D are viable.

Since y < 10√3, only answer choice D is viable.

_____

If you want to solve this using trig relations, you can recall that the sides of a 30°-60°-90° triangle have the ratios 1 : √3 : 2. This means short side y is half the length of the hypotenuse 10√3, so y = 5√3. It also means longer side x is √3 times y, so is x = (5√3)√3 = 5·3 = 15.

  x = 15; y = 5√3

6 0
3 years ago
Please help logarithms!
nlexa [21]

Given:

\log_34\approx 1.262

\log_37\approx 1.771

To find:

The value of \log_3\left(\dfrac{4}{49}\right).

Solution:

We have,

\log_34\approx 1.262

\log_37\approx 1.771

Using properties of log, we get

\log_3\left(\dfrac{4}{49}\right)=\log_34-\log_349      \left[\because \log_a\dfrac{m}{n}=\log_am-\log_an\right]

\log_3\left(\dfrac{4}{49}\right)=\log_34-\log_37^2      

\log_3\left(\dfrac{4}{49}\right)=\log_34-2\log_37          [\log x^n=n\log x]

Substitute \log_34\approx 1.262 and \log_37\approx 1.771.

\log_3\left(\dfrac{4}{49}\right)=1.262-2(1.771)

\log_3\left(\dfrac{4}{49}\right)=1.262-3.542

\log_3\left(\dfrac{4}{49}\right)=-2.28

Therefore, the value of \log_3\left(\dfrac{4}{49}\right) is -2.28.

5 0
3 years ago
Brainliest plz helpppppp<br> 4.5-3(x+2.7)=7(8.1-4x)
Fofino [41]
X=2.412 is the correct answer
8 0
3 years ago
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