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aev [14]
3 years ago
12

BRAINLIEST PLLLLLLLZZZZZZZ

Mathematics
1 answer:
baherus [9]3 years ago
8 0
The answer would be 3
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Find the measure of the sides of angle ABC with vertices A(1,5), B(3,-2), and C(-3,0). Classify the triangle
Charra [1.4K]

Answer:

AB=\sqrt{53},\ BC=\sqrt{40},\ CA=\sqrt{41}\\It\ is\ an\ acute\ triangle

Step-by-step explanation:

The distance between two points (x_1,y_1),\ (x_2,y_2) is given by \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}.

Here A(1,5),\ B(3,-2),\ C(-3,0) are the vertices of a triangle.

AB=\sqrt{(-2-5)^2+(3-1)^2}=\sqrt{(-7)^2+(2)^2}=\sqrt{49+4}=\sqrt{53}=7.28\ unit\\\\BC=\sqrt{(0+2)^2+(-3-3)^2}=\sqrt{(2)^2+(-6)^2}=\sqrt{4+36}=\sqrt{40}=6.32\ unit\\\\CA=\sqrt{(5-0)^2+(1+3)^2}=\sqrt{(5)^2+(4)^2}=\sqrt{25+16}=\sqrt{41}=6.40\ unit

Longest side=AB

AB^2=53\\BC^2+CA^2=40+41=81\\\Rightarrow AB^2

Hence this is an acute triangle.

6 0
3 years ago
What do the numbers listed for an element on the periodic table represent?
maria [59]
Im sure you have your answer by now but would you mind posting the answer
8 0
4 years ago
Need some help with this question!
Veronika [31]
1. solve for x in first to just find nterms of y

x=12-y
sub that for x in other one
first divide that one by 2 to make it easier
2x-y=18
2(12-y)-y=18
24-2y-y=18
24-3y=18
minus 24 both sides
-3y=-6
divide -3
y=2

D is answer




2.
find intersection of x+y=5 and -2x+3y=6
or easiers, just test the intersections
wait, they all intersect in the same place
this is super easy
pick ANY point that is in that reigon and see if it is true

A, if we pick lets say (5,5)
that is false for x+y<5
not A

B
pick (10,0)
false for first one
not B

C
pick (0,0)
true for first
false for 2nd
not C


D. pick (-10,0)
true for first
true for 2nd


answer is D


answer is D for both questions
6 0
3 years ago
Quadratic equations Please Help Me!!!!!!
igor_vitrenko [27]

The roots are 1 +√7 and 1 -√7.

<h3>What is Quadratic equation?</h3>

A quadratic equation in the variable x is an equation of the form ax² + bx + c= 0, where a, b, c are real numbers, a≠0

Given equation:

y= x²+2x-6

First,

Half the coefficient of x and add and subtract the square of (b/2)

y= x²+2x-6+(1)²-(1)²

y= x²+2x+(1)² -6 -(1)²

y= (x+1)² -7

Now, equate y=0

(x+1)² -7 =0

(x+1)² = 7

x+1= ±√7

x=1 ±√7

Hence, the roots are 1 +√7 and 1 -√7.

Learn more about quadratic equation here:

brainly.com/question/1962219

#SPJ1

7 0
2 years ago
8 - 2 3/5 <br><br> ANSWER ASAPPPPPP <br> TO BE BRAINLISET<br> AND EXPLAIN HOW AND BE RIGHT
kompoz [17]

Answer:

5 2/5

Step-by-step explanation:

sorry, I know the answer, but don't know how to explain in words

3 0
3 years ago
Read 2 more answers
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