Ask question

Ask question

All categories

3 years ago

14

Hich of the following statements is true about what happens during a chemical reaction?

1 answer:

postnew [5]3 years ago

6 0

I believe it is <span>d. the bonds of both the reactants and the products are formed.</span>

You might be interested in

What is the difference between saturated and unsaturated fats answers?

anyanavicka [17]

Saturated fats are when fatty acid contains carbon that are connected by a single bond. Unsaturated fats are when one or more carbons form a double bond with another carbon.

5 0

3 years ago

Read 2 more answers

Which statement correctly explains whether or not this equation is a balanced equation? KMnO4 + HCl → KCl + MnCl2 + H2O + Cl2

boyakko [2]

The correct answer is A. The equation is not balanced because the number of atoms of each element on the left is not equal to their numbers on the right.

There is 1 chlorine atom on the left. However, there are 5 chlorine atoms on the right.
There is 1 hydrogen atom on the left, but 2 hydrogen atoms on the right.
There are 4 oxygen atoms on the left, but 1 oxygen atom on the right
There is 1 manganese atom on the left and right side of the equation.
There is also 1 potassium atom on the left and right side.

The equation is clearly not balanced.

5 0

3 years ago

Calculate the Equilibrium constant Kc at 25 C from the free - energy change for the following reaction . Zn(s) + 2Ag+(aq)<---

FinnZ [79.3K]

Answer: $Kc=1.24*10^5^2$

Explanation: For the given reaction:

$Kc=\frac{[Zn^+^2]}{[Ag^+]^2}$

Concentrations of the ions are not given so we need to think about another way to calculate Kc.

We can calculate the free energy change using the standard cell potential as:

$\Delta G^0=-nFE^0_c_e_l_l$

$E^0_c_e_l_l$ can be calculated using standard reduction potentials.

Standard reduction potential for zinc is -0.76 V and for silver, it is +0.78 V.

$E^0_c_e_l_l$ = $E^0_c_a_t_h_o_d_e+E^0_a_n_o_d_e$

Reduction takes place at anode and oxidation at cathode. As silver is reduced, it is cathode. Zinc is oxidized and so it is anode.

$E^0_c_e_l_l$ = 0.78 V - (-0.76 V)

$E^0_c_e_l_l$ = 0.78 V + 0.76 V

$E^0_c_e_l_l$ = 1.54 V

Value of n is two as two moles of electrons are transferred in the cell reaction F is Faraday constant and its value is 96485 C/mol of electron .

$\Delta G^0=-(2*96485*1.54)$

$\Delta G^0$ = -297173.8 J

Now we can calculate Kc using the formula:

$\Delta G^0=-RTlnKc$

T = 25+273 = 298 K

R = $8.314JK^-^1mol^-^1$

--297173.8 = -(8.314*298)lnKc

297173.8 = 2477.572*lnKc

$lnKc=\frac{297173.8}{2477.572}$

lnKc = 119.946

$Kc=e^1^1^9^.^9^4^6$

$Kc=1.24*10^5^2$

5 0

3 years ago

there is a bell at the top of a tower that is 50 m high. The bell weighs 190N. the bell has _____________energy. Calculate it

Sedbober [7]

Answer:

9,500J

Explanation:

Distance= 50m

Force = 190N

Energy = Force x distance

= 190 x 50

= 9,500J

4 0

3 years ago

when 5 moles of ion oxide react with 25 moles of carbon monoxide what is the moles of the product formed when one of the reagent

user100 [1]

Answer: 25 moles of product are formed.

Explanation:

The balanced chemical equation will be :

$Fe_2O_3+3CO\rightarrow 2Fe+3CO_2$

According to stoichiometry :

1 mole of $Fe_2)_3$ require = 3 moles of $CO$

Thus 5 moles of $Fe_2O_3$ will require= $\frac{3}{1}\times 5=15moles$ of $CO$

Thus $Fe_2O_3$ is the limiting reagent as it limits the formation of product and $CO$ is the excess reagent.

As 4 moles of reactant give = 5 moles of product

Thus 20 moles of reactants will give = $\frac{5}{4}\times 20=25moles$ of products

4 0

2 years ago