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3 years ago

Hich of the following statements is true about what happens during a chemical reaction?

Chemistry

1 answer:

postnew [5]3 years ago

6 0

I believe it is d. the bonds of both the reactants and the products are formed.

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5. At 20°C, the water autoionization constant, Kw, is 6.8 ´ 10–15. What is the H3O+ concentration in neutral water at this tempe

rjkz [21]

Explanation:

Let us assume that the concentration of [ $OH^{-}$ and $H^{+}$ is equal to x. Then expression for $K_{w}$ for the given reaction is as follows.

$K_{w} = [OH^{-}][H^{+}]$

$K_{w} = x^{2}$

$6.8 \times 10^{-15} = x^{2}$

Now, we will take square root on both the sides as follows.

$\sqrt{6.8 \times 10^{-15}} = \sqrt{x^{2}}$

$[H^{+}] = 8.2 \times 10^{-8}$ M

Thus, we can conclude that the $H_{3}O^{+}$ concentration in neutral water at this temperature is $8.2 \times 10^{-8}$ M.

8 0

3 years ago

Read 2 more answers

Measure and pour a half cup (8 tablespoons) of tap water into the small container. Measure and record the temperature of the wat

omeli [17]

Answer:

around 50–55 degrees.

Explanation:

I believe this would be it because chemical reactions haven't happened yet. This is the usual tempurature for tap water. :)

4 0

3 years ago

Read 2 more answers

How to balance lead and silver acetate yields lead (||) acetate and silver

arsen [322]

The given elements put into an equation using their symbols are as follows:
Pb + $AgC_{2}H_{3}O_{2}$ = $Pb(II){(C_{2}H_{3}O_{2})_2}$ + Ag

Since there are 2 Pb on the right side of the equation, you would change the coefficient of Pb on the left side to 2:
2Pb + $AgC_{2}H_{3}O_{2}$ = $Pb(II){(C_{2}H_{3}O_{2})_2}$ + Ag

Since there are 2 Acetate on the right side of the equation, you would change the coefficient of Silver Acetate on the left side to 2:
2Pb + $2AgC_{2}H_{3}O_{2}$ = $Pb(II){(C_{2}H_{3}O_{2})_2}$ + Ag

Now there are 2 Silver on the left side, so you change the coefficient of Silver on the right side to 2:
2Pb + $2AgC_{2}H_{3}O_{2}$ = $Pb(II){(C_{2}H_{3}O_{2})_2}$ + 2Ag

That is your final equation

The coefficients are 2 + 2 = 1 + 2

3 0

3 years ago

What is the lower concentration limit (vol%) at which a mixture of ethanol in air can explode?

liubo4ka [24]

Answer:

Lower explosive limit (LEL) of ethanol = 3.3%

Explanation:

In the case of alcohol, ethanol presents certain fire hazards. Its momentary flash point is 55ºF (12.9ºC), while the momentary flash point of gasoline is -45ºF (-42.8ºC), and the E85 mixture ranges between -20ºF and -4ºF (between -28 , 9ºC and -20ºC), and has a wider range of flammability limits than gasoline. For emergency response teams, this implies that during a release of the typical ethanol / gasoline mixture, the fuel can be expected to behave like gasoline: It is heavier than air - as we mentioned earlier - and can produce vapors and form flammable mixtures in the air, under most environmental conditions.

General properties and comparison with other inflambles products:

Flash point momentary Gasoline = -45 ° F

Ethanol = 55 ° F

E 85 = between -20º and -4º F

Flammability limits

Lower explosive limit (LEL) of ethanol = 3.3%

Upper Explosive Limit (UEL) = 19%

Lower explosive limit (LEL) of the mixture E 85 = 1.4%

Upper Explosive Limit (UEL) 85 = 19%

Lower explosive limit (LEL) of gasoline = 1.4%

Upper Explosive Limit (UEL) = 7.6%

They have a wider range than gasoline

4 0

3 years ago

I need help please! I will mark brainliest

Fittoniya [83]

Answer: I think it's C

Explanation: I hope this helps (Sorry if it doesn't)

8 0

1 year ago