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Vaselesa [24]
3 years ago
14

Glenn is heating water in a teakettle. The hotter water at the bottom of the kettle rises. The cooler water near the top sinks a

nd warms. Which kind of transfer of heat is this?
conduction
convection
radiation
transmission
Chemistry
2 answers:
alexandr402 [8]3 years ago
5 0
B. convection

Hope this helps!
san4es73 [151]3 years ago
3 0

Answer: Option (b) is the correct answer.

Explanation:

A process in which a fluid is heated then cold material (more dense) sinks at the bottom whereas hotter material (less dense) rises at the top is known as convection.

In convection, heat transfers from burner to the vessel and further it reaches to the fluid present into the vessel.

Therefore, we can conclude that the given situation represents convection as the kind of transfer of heat.

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What happens when energy is transferred through a wave?
Alexeev081 [22]

In electromagnetic waves, energy is transferred through vibrations of electric and magnetic fields. In sound waves, energy is transferred through vibration of air particles or particles of a solid through which the sound travels.

5 0
3 years ago
Which of the following would increase friction?
KiRa [710]
B. Sand.

Sand would definitely increase friction because of the roughness of it surface. When its surface comes with another rough surface it would tend to increase friction. All other options given tend to reduce friction one way or the other.
5 0
3 years ago
Help me to balance this equations pls!<br> C3H8 02 CO+H20<br> Thank you
vichka [17]

Answer:

2C3H8 402 6CO+8H20

Explanation:

8 0
3 years ago
In CaSO4, the oxidation number of Ca is<br> that of S is<br> and that of O is
Assoli18 [71]

Answer: In CaF2, the oxidation number of Ca is +2

, and that of F is -1

. In H2SO4, the oxidation number of H is +1

, that of S is +6

, and that of O is -2

. In CaSO4, the oxidation number of Ca is +2

, that of S is +6

, and that of O is -2

. In HF, the oxidation number of H is +1

, and that of F is -1

7 0
3 years ago
A sample of an unknown gas occupies 5.51 L at 1.31 atm. What pressure would thisgas exert in a 0.520 L container if the temperat
weeeeeb [17]

Answer:

P₂ = 13.9 atm (3 sig. figs.)

Explanation:

The pressure (P), Volume (V) relationship with Temperature (T) & mass (n) held constant is an inverse proportionality. That is Boyles Law ...

P ∝ 1/V => P = k/V => k = P·V

For two pressure-volume conditions, the proportionality constant (k) remains constant where k₁ = k₂ and P₁·V₁ = P₂·V₂ => P₂ = P₁·V₁/V₂

Given:

P₁ = 1.31 atm.

V₁ = 5.51 L

P₂ = ?

V₂ = 0.520 L

V₂ = (1.31 atm)(5.51L)/(0.520L) = 13.88096154 atm (calc. ans.) = 13.9 atm (3 sig. figs.)

5 0
3 years ago
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