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zubka84 [21]
3 years ago
8

When originally purchased, a vehicle had an estimated useful life of 8 years. the vehicle cost $23,000 and its estimated salvage

value is $1,500. after 4 years of straight-line depreciation, the asset's total estimated useful life was revised from 8 years to 6 years and there was no change in the estimated salvage value. the depreciation expense in year 5 equals:?
Mathematics
1 answer:
maw [93]3 years ago
3 0
<span>We first calculate the annual straight-line depreciation for the starting 8-year useful lifespan. This is given by the value minus the salvage value (23,000 - 1,500) divided by the 8 year lifespan, resulting in annual depreciation of 2,687.50 dollars. After four years at this rate, the vehicle has depreciated in value by 2,687.50 * 4 dollars (10,750) and has a present value of 12,250 dollars. The useable life is then reduced by 2 years so we must recalculate the straight-line depreciation. This is given by present value minus salvage cost (12,250 - 1,500) divided by the remaining 2 years of usable life. This results in a depreciation expense in both years 5 and 6 of $5,375.</span>
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1. A (x²-4y)³
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5 0
3 years ago
Describe how modern entertainment has begun to reflect the changing makeup of families in America.
GarryVolchara [31]

It should be noted that modern entertainment has played a vital role in shaping African culture and homes.

Through modern entertainment, Africans views on marriages have changed. Most African men now marry one wife which was quite different in the olden days when it was believed that an increase in the number of wives one had was used to show superiority.

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brainly.com/question/773944

8 0
2 years ago
If 3220 = 80+7, what is the value of c?
Setler79 [48]

Answer:

Correct option is

C

36.25

Modal class =30−40

So we have, l=30,f0=12,f1=32,f2=20 and h=10

⇒  Mode=l+2f1−f0f2f1−f0×h

                  =30+2×32−12−2032−12×10

                  =30+6.25

                  =36.25

∴  Mode =36.25

8 0
3 years ago
Which ordered pair (a, b) is a solution to the given system of linear equations? -2a+3b=14
Stels [109]

Answer:

The solution of the system is the ordered pair (-13,-4)

Step-by-step explanation:

we have

-2a+3b=14 -----> equation A

a-4b=3 ----> equation B

Solve the system by elimination

Multiply by 2 both sides equation B

2(a-4b)=2(3)

2a-8b=6 ----> equation C

Adds equation A and equation C

-2a+3b=14\\2a-8b=6\\-------\\3b-8b=14+6\\-5b=20\\b=-4

<em>Find the value of a</em>

substitute the value of b in any equation (i take equation B)

a-4(-4)=3

a+16=3

a=-13

therefore

The solution of the system is the ordered pair (-13,-4)

6 0
3 years ago
Read 2 more answers
Hmm who is smart enough for this :)
Goryan [66]

Answer:

1

-\frac{9}{15}

-0.7

Step-by-step explanation:

Both -\frac{9}{15} and -0.7 are negative so therefore, 1 is the greatest

-\frac{9}{15} is -0.6 which is greater than -0.7 so it's the 2nd greatest

and -0.7 is the least

7 0
3 years ago
Read 2 more answers
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