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cestrela7 [59]
3 years ago
7

Which expression is equivalent to sqrt10/4sqrt8

Mathematics
2 answers:
Irina-Kira [14]3 years ago
8 0

Answer:

Step-by-step explanation:

Since it's a division we need to look for a common factor to cancel

so first we try to break the numbers to there prime factors

\frac{\sqrt{10} }{4\sqrt{8} } = \frac{\sqrt{2.5} }{4\sqrt{2.2.2} }

So , now we try to factors that are common in top and bottom

= \frac{\sqrt{2} \sqrt{5}}{4\sqrt{2}\sqrt{4} }

common factor is sqrt 2 so lets cancel it

we get

\frac{\sqrt{5} }{4\sqrt{4} }

\frac{\sqrt{5} }{8}

zubka84 [21]3 years ago
6 0
We can break √10 into √2 • √5, and √8 into √2 • √4, or, simplifying √4 to 2, 2 • √2. Our expression now becomes

(√2 • √5) / (4 • 2 • √2)

Cancelling the √2 in the numerator and denominator gets us

√5/(4 • 2), or √5/8.

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What are the points of discontinutity y=(x-3)/x^2-12x+27
madreJ [45]

Answer:

(3, -\frac{1}{6})

Step-by-step explanation:

We can rewrite the equation as

y = \frac{x - 3}{(x - 3)(x - 9)}

Notice that we have x - 3 in both the numerator and the denominator, so it looks like we can divide it out. However, what if x - 3 is 0? Then we would have y = \frac{0}{0 \times (x - 9)} = \frac{0}{0}, which is undefined. So although it looks like the numerator and denominator can be simplified, the resulting function we would get from simplification would not have the same behavior as this one (since such a function would be defined for x = 3, but this one is not).

A point of discontinuity refers to a particular point which is included in the simplified function, but which is not included in the original one. In this case, the point which is not included in the unsimplified function is at x = 3. In the simplified version of the function, if we plug in x = 3, we get

y = \frac{1}{((3) - 9)} = -\frac{1}{6}

So the point (3, -\frac{1}{6}) is our only point of discontinuity.

It's also important to distinguish between specific points of discontinuity and vertical asymptotes. This function also has a vertical asymptote at x = 9 (since it causes the denominator to be 0), but the difference in behavior is that in the case of the asymptote, only the denominator becomes 0 for a specific value of x

5 0
3 years ago
Read 2 more answers
What might weigh 20 kg?
KatRina [158]
The heavy suitcase.

A small car would still weigh quite a lot, a tablet would weigh a lot less than that, and a watermelon is around 2kg (depends).
7 0
2 years ago
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Graph each absolute value function. State the domain, range, and y-intercept.
Paraphin [41]

Answer:

i)D:x\in R

ii)R: y\ge-3

iii) Y-int:(0,-1)

Step-by-step explanation:

i) The given absolute value function is;

f(x)=|x+2|-3.

The absolute value function is defined for all real values of x.

The domain is all real numbers.

ii) The range is all y-values that will make x defined.

The given function,

f(x)=|x+2|-3.

has vertex at, (-2,-3) and opens upwards.

This implies that, the minimum y-value is -3.

The range is y\ge-3

iii) To find the y-intercept substitute x=0 in to the function.

f(0)=|0+2|-3.

f(0)=|2|-3.

f(0)=2-3.

f(0)=-1.

The y-intercept is (0,-1)

See attachment for graph.

6 0
3 years ago
Drag and drop the correct number to complete the equation.
uysha [10]

Answer:

20/33

Step-by-step explanation:

because math says so

4 0
3 years ago
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Can yall help meee please
alexira [117]

Answer:

jupiters \: mass \: is \: approximatelty \:  \\   \boxed{{6 \times 10}^{3} \: kg}  \: times, \:  \\ more \: than \: mercurys \: mass

Step-by-step explanation:

............................................................... \\ in \: other \: to \: get \: right \: ans \to \\ you \: divide \: mass \: of \: jupiter \: by \: the \: mass \\  \: of \: mercury : \: so \to \\ ............................................................... \\ jupiters \: mass = 1.898 { \times 10}^{27}  \: kg \\ mercurys \: mass =3.3 \times  {10}^{23}   \: kg \\ their \: mass \: ratio \: is :  \\  =  \frac{1.898 { \times 10}^{27}}{3.3 \times  {10}^{23}}  = 0.5751515152 \times  {10}^{4}   =  \\  \boxed{5,751.515152} \\ hence \: jupiters \: mass \: is \: approximatelty \:  \\  {6 \times 10}^{3}  \: times \: more \: than \: mercurys \: mass

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2 years ago
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