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torisob [31]
3 years ago
12

Explain and correct the error in the example above

Mathematics
1 answer:
PtichkaEL [24]3 years ago
8 0

Answer:

C = 28.26  cm

Step-by-step explanation:

The figure shows a circle of diameter 9 inches.

The person has taken radius r as 9 inches which is wrong.

The radius must be (9/2) = 4.5 inches, such that,

Circumference = 2πr

= 2×3.14×4.5

= 28.26  cm

Hence, this is the required solution.

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12 + z = 15


12 - 12 + z = 15 - 12


0 + z = 3


z = 3


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Step-by-step explanation:

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the graph is in link

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A) solution is overlapping shaded part

B) (10,5)

plug in point in inequalities and check if it's true; if it's true you showed that solution is correct

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Algebra 2 help. Solving equations containing two radicals
Marysya12 [62]

These are 3 questions and 3 answers.

Question 1.

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Explanation:

1) Equation A

\sqrt{x^2+3x-6}=\sqrt{x+2}\\ \\  x^2+3x-6=x+2\\ \\  x^2+2x-8=0\\ \\  (x+4)(x-2)=0\\ \\  x=-4 ; x =2

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Which is not defined, so this is a extraneous solution.

2) Equation B.

Since it is a cube root, it is defined for any (negative, zero, and positive) values of x.

Question 2.

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\sqrt[3]{5x-2} -\sqrt[3]{4x} =0\\ \\  \sqrt[3]{5x-2} =\sqrt[3]{4x}\\  \\  (\sqrt[3]{5x-2} )^3=(\sqrt[3]{4x})^3\\  \\  5x-2=4x\\ \\  5x-4x=2\\ \\  x=2

3) Question 3.

Answer: c - 2 = 25 + c + 10√c

Explanation:

\sqrt{c-2} -\sqrt{c} =5\\ \\ \\  \sqrt{c-2} =\sqrt{c} +5\\ \\  (\sqrt{c-2})^{2}  =(\sqrt{c}+5)^2\\  \\  c-2=c+10\sqrt{c} +25\\ \\  c-2=25+c+10\sqrt{c}

4 0
3 years ago
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