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3 years ago

Determine all the transformations that have happened to f(x) = (x + 4)2 + 2 compared to

Mathematics

1 answer:

Sav [38]3 years ago

3 0

Answer:

Folow the steps to learn what transformations were determined.

Step-by-step explanation:

First we would have to graph the parent function which is f(x) = x^2. Start by finding your x and y values. Find the y values by plugging in the x values into the parent function.

X Y

2 4

1 1

0 0

-1 1

-2 4

Once these points are plotted you can start determining what are the transformations. Find the difference between the parent function and f(x) = (x + 4)^2 + 2 by looking below.

Vertical Shifts:

f(x) + c moves up,

f(x) - c moves down.

Horizontal Shifts:

f(x + c) moves left,

f(x - c) moves right.

The parent function has to be transformed left 4 and up 2. In order to do this shift each point from earlier left 4 and then up 2. In conclusion you will have two functions graphed (parent function and the transformed function).

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Can somebody help me out ?? please ..

kotegsom [21]

Y=35
Z=112
Hope this helps you and you have a good day and yes I did calculate this

8 0

3 years ago

Solve 6 < x + 5 < 11

Vanyuwa [196]

Answer:

I think it should be 1 < x ≤ 6

Step-by-step explanation:

7 0

3 years ago

May I also have help with this question

KATRIN_1 [288]

The independent variable (the one they want) is the # of hours worked, since that determines the price.

All the other answers contain information not included in the problem

5 0

4 years ago

Read 2 more answers

Arrange the steps to perform this subtraction operation in the correct order.

taurus [48]

Answer:

=1.23*10^6

Step-by-step explanation:

We have to calculate

(1.93*10^7 )-(9.7*10^6)

In order to add or subtract two numbers in scientific notation, we have to make sure that the power of exponents in both numbers is same.

We have to reduce the power of 10 in first number from 7 to 6

So,

Step 1:

1.93*10^7=1.93*10*10^6

=10.93*10^6

Now,

Step 2:

=(1.93*10^7 )-(9.7*10^6 )

= 10.93*10^6- 9.7*10^6

Step 3:

=(10.93-9.7)*10^6

=1.23*10^6

7 0

4 years ago

Read 2 more answers

A recent study found that 51 children who watched a commercial for Walker Crisps (potato chips) featuring a long-standing sports

hichkok12 [17]

Answer:

The claim is that the mean amount of Walker Crisps eaten was significantly higher for the children who watched the sports celebrity- endorsed Walker Crisps commercial

The kind of test to use is a t -test because a t -test is used to check if there is a difference between means of a population

$t = 3.054$

The p-value is $p-value = P(Z > 3.054) = 0.0011291$

The conclusion is

There is sufficient evidence to conclude that the mean amount of Walker Crisps eaten was significantly higher for the children who watched the sports celebrity- endorsed Walker Crisps commercial

The test statistics is

Step-by-step explanation:

From the question we are told that

The first sample size is $n_1 = 51$

The first sample mean is $\mu_1 = 36$

The second sample size is $n_2 = 41$

The second sample size is $\mu_2 = 25$

The first standard deviation is $\sigma _1 = 21.4 \ g$

The second standard deviation is $\sigma _2 = 12.8 \ g$

The level of significance is $\alpha = 0.05$

The null hypothesis is $H_o : \mu_1 = \mu_ 2$

The alternative hypothesis is $H_a : \mu_1 > \mu_2$

Generally the test statistics is mathematically represented as

$t = \frac{\= x_1 - \= x_2}{ \sqrt{ \frac{s_1^2}{n_1} + \frac{s_2^2}{n_2} } }$

=> $t = \frac{ 36 - 25}{ \sqrt{ \frac{ 21.4^2}{51} + \frac{ 12.8^2}{41} } }$

=> $t = 3.054$

The p-value is mathematically represented as

$p-value = P(Z > 3.054)$

Generally from the z table

$P(Z > 3.054) = 0.0011291$

=> $p-value = P(Z > 3.054) = 0.0011291$

From the values obtained we see that $p-value < \alpha$ so the null hypothesis is rejected

Thus the conclusion is

There is sufficient evidence to conclude that the mean amount of Walker Crisps eaten was significantly higher for the children who watched the sports celebrity- endorsed Walker Crisps commercial

5 0

3 years ago