The spring has been stretched 0.701 m
Explanation:
The elastic potential energy of a spring is the potential energy stored in the spring due to its compression/stretching. It is calculated as
where
k is the spring constant
x is the elongation of the spring with respect to its equilibrium position
For the spring in this problem, we have:
E = 84.08 J (potential energy)
k = 342.25 N/m (spring constant)
Therefore, its elongation is:
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Answer:
= 1.132 A
Explanation:
Given that:
A 120-V rms voltage at 60.0 Hz which applied across an inductor, capacitor and a 100- resistor in series.
If the maximum value of the current in this circuit = 1.60 A
what is the rms value of the current in this circuit i.e the = ????
The relation between and
can be expressed by the formula:
=
1.60 = 1.414 *
=
= 1.132 A
Thus, the value of the current this circuit = 1.132 A
Answer:
w = 1.976 rpm
Explanation:
For simulate the gravity we will use the centripetal aceleration , so:
where w is the angular aceleration and r the radius.
We know by the question that:
r = 60.5m
= 2.6m/s2
So, Replacing the data, and solving for w, we get:
W = 0.207 rad/s
Finally we change the angular velocity from rad/s to rpm as:
W = 0.207 rad/s = 0.207*60/(2)= 1.976 rpm