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77julia77 [94]
2 years ago
9

Can you figure out.... between 25 and 27.5? Plz?

Mathematics
1 answer:
Rudiy272 years ago
6 0

Answer:

I am just adding an answer so the other person can have brainliest...

Step-by-step explanation:

They are correct

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The function h(t)=-4.87t^2+18.75t is used to model the height of an object projected in the air, where h(t) is the height in met
rodikova [14]
Looking at the graph you can see that the domain of the function is:
 [0, 3.85]
 To find the range of the function, we must follow the following steps:
 Step 1)
 
Evaluate for t = 0
 h (0) = - 4.87 (0) ^ 2 + 18.75 (0)
 h (0) = 0
 Step 2) 
 find the maximum of the function:
 h (t) = - 4.87t ^ 2 + 18.75t
 h '(t) = - 9.74 * t + 18.75
 -9.74 * t + 18.75 = 0
 t = 18.75 / 9.74
 t = 1.925051335
 We evaluate the function at its maximum point:
 h (1.925051335) = - 4.87 * (1.925051335) ^ 2 + 18.75 * (1.925051335)
 h (1.93) = 18.05
 The range of the function is:
 [0, 18.05]
 Answer:
 
Domain: [0, 3.85]
 Range: [0, 18.05]
 option 1
3 0
3 years ago
4n-6m=-2 when n=-2,0,2
guapka [62]

For m it’s 1,1/3and -5/3 you will get different values when plug the different values of n

4 0
3 years ago
The smaller pyramid has a volume of 52 inches. What
astraxan [27]

Answer:

175.5 in^3

Step-by-step explanation:

5 0
3 years ago
If the area of a rectangle equals 30 cm² and the perimeter is equal to 26 cm. Find the length and width of the rectangle.​
Kamila [148]

Answer:

Length = 10 & width = 3

Step-by-step explanation:

Perimeter = Length + Length + Width + Width

26 = 2Length + 2 Width

26 = 2 ( Length + Width )

13 = Length + width

13 - Length = Width EQUATION 1

Area = Length X Width

30 = Length X ( 13 - Length )

30 = 13Length - Length ^2

Length ^2 - 13Length + 30 = 0

( Length - 3 )( Length - 10 )

Length = 3 or Length = 10

Therefore Length = 10

From equation 1

13 - Length = Width

13 - 10 = width

width = 3

8 0
1 year ago
What is the LCD of 3k/40 and k/18?<br><br> ​
Dmitriy789 [7]

Answer:

360.

Step-by-step explanation:

3 0
3 years ago
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